Question

我正在实现一些基本的3D物理引擎。对于球体到球体的碰撞，我遵循这个tutorial。我有2个移动球体的问题。我想我找到的方式可能有些问题＆＃34;缩短了速度＆＃34;

maxConcurrentOperations = 2

在我的测试场景中，速度矢量是（-2，-4，-2）和（1,2,1）。因此＆＃34; shortVel＆＃34;变得实际上大于原始的速度。

bool collidingDSmove(Sphere sphere){
    // Early Escape test: if the length of the movevec is less
    // than distance between the centers of these circles minus 
    // their radii, there's no way they can hit.

// ***金额不在0和1之间

    vec3 shortVel = sphere.velocity.substract(velocity);
    vec3 fromAtoBCenter = position.substract(sphere.position);
    float distSquare = fromAtoBCenter.getLengthSquare();
    float sumRadii = (radius + sphere.radius);
    distSquare -= sumRadii*sumRadii;
    if (shortVel.getLengthSquare() < distSquare){
        return false;
    }

    // Normalize the movevec
    vec3 N = shortVel.normalize();

    // Find C, the vector from the center of the moving 
    // circle A to the center of B
    vec3 C = sphere.position.substract(position);

    // D = N . C = ||C|| * cos(angle between N and C)
    float D = N.dot(C);

    // Another early escape: Make sure that A is moving 
    // towards B! If the dot product between the movevec and 
    // B.center - A.center is less that or equal to 0, 
    // A isn't isn't moving towards B
    if (D <= 0){
        return false;
    }
    // Find the length of the vector C
    float lengthCSquare = C.getLengthSquare();

    float F = (lengthCSquare)-(D * D);

    // Escape test: if the closest that A will get to B 
    // is more than the sum of their radii, there's no 
    // way they are going collide
    float sumRadiiSquared = sumRadii * sumRadii;
    if (F >= sumRadiiSquared){
        return false;
    }

    // We now have F and sumRadii, two sides of a right triangle. 
    // Use these to find the third side, sqrt(T)
    double T = sumRadiiSquared - F;

    // If there is no such right triangle with sides length of 
    // sumRadii and sqrt(f), T will probably be less than 0. 
    // Better to check now than perform a square root of a 
    // negative number. 
    if (T < 0){
        return false;
    }

    // Therefore the distance the circle has to travel along 
    // movevec is D - sqrt(T)
    float distance = D - sqrt(T);

    // Get the magnitude of the movement vector
    float mag = velocity.getLength();

    // Finally, make sure that the distance A has to move 
    // to touch B is not greater than the magnitude of the 
    // movement vector. 
    if (mag < distance){
        return false;
    }

我的vec3课程如下：

    float amount = shortVel.normalize().getLength() / velocity.getLength();
    // Set the length of the movevec so that the circles will just 
    // touch
    velocity = velocity.normalize().times(amount);
    sphere.velocity = sphere.velocity.normalize().times(amount);

    return true;
}

请你解释一下我在这里做错了什么？

这是我的更新功能。其中deltaT是2帧之间的时间间隔

class vec3 {
public:
    float x; float y; float z;
    vec3() : x(0), y(0), z(0) { }
    vec3 substract(vec3 v){
        vec3 sub;
        sub.x = x - v.x;
        sub.y = y - v.y;
        sub.z = z - v.z;
        return sub;
    }
float getLength() {
        return sqrt(x*x + y*y + z*z);
    }
float getLengthSquare() {
        return x*x + y*y + z*z;
    }
vec3 normalize(){
        vec3 n;
        n.x = x / getLength();
        n.y = y / getLength();
        n.z = z / getLength();
        return n;
    }
float dot(vec3 v) {
        return x*v.x + y*v.y + z*v.z;
    }
}

Answer 1

首先，在vec3中创建add和times函数。

如果球体s1和球体s2（位置为p（vec3），速度v（vec3），半径r（浮动）和质量m（浮动））发生碰撞，则可以执行以下操作：

// from s1 to s2
vec3 pDiff = s2.p.subtract(s1.p);
// collision detection
if (pDiff.getLength() >= s1.r + s2.r) {
    return;
}
// find direction from s1 to s2
vec3 dir = pDiff.normalize();
vec3 vDiff = s2.v.subtract(s1.v);
float fellingSpeed = vDiff.dot(dir);
// don't collide in this case
if (fellingSpeed >= 0) {
    return;
}
// perfect spheric collision
float speed1 = (2 * s2.m * fellingSpeed) / (s1.m + s2.m);
float speed2 = (fellingSpeed * (s2.m - s1.m)) / (s1.m + s2.m);
s1.v = s1.v.add(dir.times(speed1));
s2.v = s2.v.add(dir.times(speed2 - fellingSpeed));

我希望它有所帮助。

球体碰撞（C ++）

1 个答案: