def add(num1, num2):
return num1 + num2
def sub(num1, num2):
return num1 - num2
def multi(num1, num2):
return num1 * num2
def div(num1, num2):
return num1 / num2
print("\t\t\tCalculator App")
def main():
operation = input("\nWhat do you want to do: (+, -, *, /)? ")
if(operation != "+" and operation != "-" and operation != "*" and operation != "/"):
#invalid operation
print("You have entered an invalid key")
else:
var1 = int(input("Please number : "))
var2 = int(input("Please enter another number : "))
if(operation == "+"):
print("Answer is: ", add(var1, var2))
elif(operation == "-"):
print("Answer is: ", sub(var1, var2))
elif(operation == "*"):
print("Answer is: ", multi(var1, var2))
else:
print("Answer is: ", div(var1,var2))
main()
rerun = input("ReRun? (y/n)")
while(rerun == "y"):
main()
rerun = input("ReRun? (y/n) ")
else:
exit()
阅读书籍,观看视频和自学一直充满挑战。
如果这是循环此程序的正确方法,请告诉我,我确定有其他选择。
答案 0 :(得分:1)
如果您的意思是在底部重新运行循环,则以下内容可能更清晰:
while True:
main()
if input("ReRun? (y/n) ") == 'n':
break
应该注意的是,如果用户输入了不期望的内容,则默认重新运行。
答案 1 :(得分:0)
我会做类似
的事情operators = dict()
operators['+'] = lambda x,y: x+y
operators['-'] = lambda x,y: x-y
operators['*'] = lambda x,y: x*y
operators['/'] = lambda x,y: x/y
def main():
operation = input("\nWhat do you want to do: (+, -, *, /)? ")
if operation in operators:
var1 = int(input("Please number : "))
var2 = int(input("Please enter another number : "))
print("Answer is: ", operators[operation](var1, var2))
else:
print("You have entered an invalid key")
while True:
main()
if input("ReRun? (y/n) ") == 'n':
break
我相信它更易于扩展,更容易扩展(添加新操作符)