我正在重构代码以不使用std :: vector< byte>。我该如何做到这一点?
不知何故,WSASend()更喜欢让WSABUF.buf指向std :: vector< byte>它适用于图像文件(.jpg,.png等)。
在测试期间,image / * mimetypes返回net :: ERR_CONTENT_LENGTH_MISMATCH。
byte* HttpResponse::GetResponse2(ULONG *len)
{
DWORD dwThreadId = GetCurrentThreadId();
char *buffer = (char*)malloc(DATA_BUFSIZE);
memset(buffer, 0, DATA_BUFSIZE);
std::vector<byte> binbuffer = m_sbResponse;
std::string ctstr;
ctstr.assign(contenType.begin(), contenType.end());
size_t siz = binbuffer.size();
std::string ssiz = std::to_string(siz);
strcpy_s(buffer, DATA_BUFSIZE, resp_ok);
strcat_s(buffer, DATA_BUFSIZE, "\n");
strcat_s(buffer, DATA_BUFSIZE, "Date: ");
strcat_s(buffer, DATA_BUFSIZE, "May 10, 2015");
strcat_s(buffer, DATA_BUFSIZE, "\n");
strcat_s(buffer, DATA_BUFSIZE, "Content-Type: ");
strcat_s(buffer, DATA_BUFSIZE, ctstr.c_str());
strcat_s(buffer, DATA_BUFSIZE, "\n");
strcat_s(buffer, DATA_BUFSIZE, "Content-Length: ");
strcat_s(buffer, DATA_BUFSIZE, ssiz.c_str());
strcat_s(buffer, DATA_BUFSIZE, "\n");
strcat_s(buffer, DATA_BUFSIZE, "\n");
int bufsiz = strlen(buffer) + binbuffer.size() + 1;
byte* buffer2 = (byte*)malloc(bufsiz);
memset(buffer2, 0, bufsiz);
strcpy_s((char*)buffer2, strlen(buffer)+1, buffer);
int n = strlen((char*)buffer2);
std::vector<byte>::iterator it;
for (it = binbuffer.begin(); it != binbuffer.end(); it++)
{
byte b = *it;
buffer2[n++] = b;
}
*len = strlen((char*)buffer2);
return buffer2;
}
我需要为WSA *设置一个属性来处理我正在尝试做的事情吗?
答案 0 :(得分:1)
尝试更像这样的东西:
byte* HttpResponse::GetResponse2(ULONG *len)
{
*len = 0;
std::ostringstream oss;
oss << resp_ok << "\n"
oss << "Date: " << "May 10, 2015" << "\n";
oss << "Content-Type: " << contenType << "\n";
oss << "Content-Length: " << m_sbResponse.size() << "\n";
oss << "\n";
std::string s = oss.str();
int bufsiz = s.length() + m_sbResponse.size();
byte* buffer2 = (byte*) malloc(bufsiz);
if (buffer2)
{
std::copy(s.begin(), s.end(), buffer2);
std::copy(m_sbResponse.begin(), m_sbResponse.end(), &buffer2[s.length()]);
*len = bufsiz;
}
return buffer2;
}
话虽如此,我强烈建议不要退回byte*
。您的GetResponse()
方法将输出std::vector<byte>
作为参数,您应该坚持使用该模型:
void HttpResponse::GetResponse2(std::vector<byte> *pv)
{
pv->clear();
std::ostringstream oss;
oss << resp_ok << "\n"
oss << "Date: " << "May 10, 2015" << "\n";
oss << "Content-Type: " << contenType << "\n";
oss << "Content-Length: " << m_sbResponse.size() << "\n";
oss << "\n";
std::string s = oss.str();
pv->reserve(s.length() + m_sbResponse.size());
std::copy(s.begin(), s.end(), std::back_inserter(*pv));
std::copy(m_sbResponse.begin(), m_sbResponse.end(), std::back_inserter(*pv));
}