Question

获得第一个字符串并且第一个双重后，程序没有得到其他字符串。

for (int i = 0; i< NUM_MOVIES; i++)
{
    cout << "Enter the name of the movie: ";
    getline(cin, names[i]);

    cout << "How much did " << names[i] << " earn <in millions>: ";
    cin >> earnings[i];
    cout << endl;
}

Answer 1

第二次拨打getline时，您实际上正在阅读换行符，因为cin >>在刚刚读取的值之后不会丢弃换行符。

所以你最终会在这个阅读不良数据的循环中结束。试试这个：

getline(cin >> std::ws, names[i]);

Answer 2

cin >> earnings[i];

这应该纠正如下

getline(cin, earnings[i])

//示例程序

#include <iostream>
#include <string>
using namespace std;

int main()
{
  string names[10];
  string earnings[10];
  for (int i = 0; i< 10; i++)
{
    cout << "Enter the name of the movie: ";
    getline(cin, names[i]);

    cout << "How much did " << names[i] << " earn <in millions>: ";
    getline(cin, earnings[i]);
    cout << endl;
}
cout<< names[0]<< names[1]<<"\n";
cout<<earnings[0] << earnings[1]<<"\n";
return 0;

}

Answer 3

问题是>>没有读过行尾，所以下面的std::getline()会这样做，而不是抓住你的下一个输入。

您可以使用std::ws（吸收空白字符）：

for (int i = 0; i< NUM_MOVIES; i++)
{
    cin >> std::ws; // clear previous line

    cout << "Enter the name of the movie: ";
    getline(cin, names[i]);

    cout << "How much did " << names[i] << " earn <in millions>: ";
    cin >> earnings[i];
    cout << endl;
}

c ++如何使用getline将完整的字符串存储到字符串数组中？

3 个答案: