Question

我想问一下curl php ...

我想从数据库中获取数据并使用php curl发送到其他PC并将其保存为纯文本。但我的问题是，系统不从数据库发送数据，只是发送我声明的数据名称。我使用fedora平台......其实我是curl php的初学者......

这里是我的代码... send.php

   <?php

   $servername = "yusufpsm";
   $username = "root";
   $password = "921217";
   $db_name = "squid";


   // Create connection
   $conn = mysqli_connect($servername, $username, $password, $db_name);

   // Check connection
   if (!$conn) {
  die("Connection failed: " . mysqli_connect_error());
  }
  echo "Connected successfully\n";

  ///////////////////////////////////////////////////////////////////////

  $sql = "SELECT domain_name, domain_content, reason FROM domain";

  $domain= $_POST['domain_name'];
  $content= $_POST['domain_content'];
  $reason = $_POST['reason'];

  $result = mysqli_query($conn, $sql);
  if (mysqli_num_rows($result) > 0) 
  {
  while($row = mysqli_fetch_assoc($result)) 

  {


  $curlHandle = curl_init();
  curl_setopt($curlHandle, CURLOPT_URL, '192.168.100.11/update.php');
  curl_setopt($curlHandle, CURLOPT_POST, 1);
  curl_setopt($curlHandle, CURLOPT_HEADER, 0);
  curl_setopt($curlHandle, CURLOPT_SSL_VERIFYPEER, 0);
  curl_setopt($curlHandle, CURLOPT_POSTFIELDS,                    'domain_name='.$domain.'domain_content='.$content. 'reason='.$reason);
  curl_setopt($curlHandle, CURLOPT_FOLLOWLOCATION,1); 
  curl_setopt($curlHandle, CURLOPT_RETURNTRANSFER, 1);

  if (!curl_exec($curlHandle)) {
  echo 'An error has occurred: ' . curl_error($curlHandle);
  }
  else {
  echo 'everything was successful';
  } 
  }
  } 
   else 
  {
  echo "0 results";
  }



   curl_close($curlHandle) ;

   mysqli_close($conn);
    ?>

这里是update.php

    <?php


    $domain_name = $_POST['domain_name'];
    $domain_content = $_POST['domain_content'];
    $reason = $_POST['reason'];

    chmod("/var/www/html/newfile.txt",0777);
    $myfile = fopen("/var/www/html/newfile.txt", "w") or die("Unable to open   file!");
    $txt = $domain_name;
    fwrite($myfile, $txt); 
    $txt = $domain_content;
    fwrite($myfile, $txt); 
    $txt = $reason;
    fwrite($myfile, $txt);
    fclose($myfile);

   ?>

Answer 1

try following code  



   <?php

       $servername = "yusufpsm";
       $username = "root";
       $password = "921217";
       $db_name = "squid";


       // Create connection
       $conn = mysqli_connect($servername, $username, $password, $db_name);

       // Check connection
       if (!$conn) {
      die("Connection failed: " . mysqli_connect_error());
      }
      echo "Connected successfully\n";

      ///////////////////////////////////////////////////////////////////////

      $sql = "SELECT domain_name, domain_content, reason FROM domain";

     /* $domain= $_POST['domain_name'];
      $content= $_POST['domain_content']; // don't know what is this
      $reason = $_POST['reason'];*/

      $result = mysqli_query($conn, $sql);
      if (mysqli_num_rows($result) > 0) 
      {
      while($row = mysqli_fetch_assoc($result)) 

      {

     $domain= $row['domain_name'];
      $content= $row['domain_content']; // get values row-wise from db
      $reason = $row['reason'];

      $curlHandle = curl_init();
      curl_setopt($curlHandle, CURLOPT_URL, '192.168.100.11/update.php');
      curl_setopt($curlHandle, CURLOPT_POST, 1);
      curl_setopt($curlHandle, CURLOPT_HEADER, 0);
      curl_setopt($curlHandle, CURLOPT_SSL_VERIFYPEER, 0);
      curl_setopt($curlHandle, CURLOPT_POSTFIELDS,                    'domain_name='.$domain.'&domain_content='.$content. '&reason='.$reason);
      curl_setopt($curlHandle, CURLOPT_FOLLOWLOCATION,1); 
      curl_setopt($curlHandle, CURLOPT_RETURNTRANSFER, 1);

      if (!curl_exec($curlHandle)) {
      echo 'An error has occurred: ' . curl_error($curlHandle);
      }
      else {
      echo 'everything was successful';
      } 
      }
      } 
       else 
      {
      echo "0 results";
      }



       curl_close($curlHandle) ;

       mysqli_close($conn);
        ?>

将数据库数据发送到一个网络中的其他PC

1 个答案: