Question

我在MySQL中有两个表：

表1

Week    From         Until
1    2015-04-01    2015-04-07
2    2015-04-08    2015-04-14
3    2015-04-15    2015-04-21
4    2015-04-22    2015-04-28

表2

Input_Date        Code
2015-04-10        123
2015-04-22        456
2015-04-25        123
2015-04-26        123

我使用此查询根据当前日期选择当前周：

SELECT Week FROM table_1 WHERE（NOW（）BETWEEN From和Until）
我需要选择“代码”并从表2中计算，其中“Code”= 123，“Input_Date”对应当前的“Week”。

*如果当前日期是2015-04-23，则“周”将是= 4

结果将是：

Week   Code  Count
 4     123     2

Answer 1

尝试 -

SELECT t1.Week, t2.Code, COUNT(*) 
FROM table_1 t1 
LEFT JOIN table_2 t2
ON t2.Input_Date BETWEEN t1.From AND t1.Until
WHERE (NOW() BETWEEN t1.From AND t1.Until) 
AND t2.Code = 123

http://sqlfiddle.com/#!9/3d2a6/16

Answer 2

在没有LEFT JOIN的情况下执行相同操作的替代方法

SELECT a.week, b.code, count(a.week) 
FROM table_1 a, table_2 b
WHERE (b.input_date BETWEEN a.from AND a.until)
AND (NOW() BETWEEN a.From AND a.Until)
AND b.code = 123

从MYSQL中的2个表中查询

2 个答案: