Question

我有一张表matches，我希望从中获得得分最高的用户：

SELECT userId,SUM(score) AS score FROM `matches` GROUP BY userId ORDER BY score DESC

此输出2列userId和score。好。现在我有一个users表，我希望得到userId的更详细的输出。例如，我希望：userId-firstName-lastName-phone-address-score。这有可能通过简单的SQL查询吗？谢谢。

Answer 1

您可以JOIN这样的表：

SELECT 
    matches.userId,
    SUM(matches.score) AS score,
    users.firstName,
    users.lastName,
    users.phone,
    users.address
FROM 
    `matches`
    JOIN users
        ON `matches`.userId=users.userId
GROUP BY 
    matches.userId,
    users.firstName,
    users.lastName,
    users.phone,
    users.address 
ORDER BY 
    score DESC

参考：

13.2.8.2 JOIN Syntax

Answer 2

SELECT userId, firstName, lastName, phone, address, SUM(score) AS score FROM matches join users on matches.user_id = users.user_id GROUP BY userId ORDER BY score DESC

Answer 3

是的，只需使用JOIN语句，例如：

SELECT m.userId, SUM(m.score) AS score, u.firstName, u.lastName FROM `matches` AS m
INNER JOIN `users` AS u ON u.userId = m.userId
GROUP BY userId ORDER BY score DESC

来自2个表的SELECT查询

3 个答案: