Question

我想知道如何按照从最小到最旧的整数/年龄顺序排列链表addressBook。我知道Collections.sort(addressBook);会按字母顺序组织列表，但我不打算在我的最终产品中真正需要它。

＆＃13;

import java.io.*;
import java.util.*;

public class ABook
{
   public static void main (String args[])
   {
       LinkedList addressBook = new LinkedList(); 
       Scanner input = new Scanner(System.in);
       int n = 0; 
       do{
       System.out.println("Would you like to add a friend? (Say Y or N)"); 
       String reply = input.nextLine();
       if(reply.equals("Y"))
       {
        System.out.println("What is the name of your friend?");
        String name = input.nextLine();
        System.out.println("What is the age of your friend?");
        int age = input.nextInt();
        Friend newFriend = new Friend(name,age);
        addressBook.add("Name: " + newFriend.name + "; " + "Age: " + newFriend.age);
        Collections.sort(addressBook);
        System.out.println("This is your Address Book so far: " + addressBook);
        n++;
    }     
      ...
}

＆＃13;

如果有人能告诉我，那就太棒了。

谢谢！

Answer 1

使用比较器。

＆＃13;

import java.io.*;
import java.util.*;

public class ABook
{
   public static void main (String args[])
   {
       LinkedList addressBook = new LinkedList(); 
      

       Scanner input = new Scanner(System.in);
       int n = 0; 
       do{
       System.out.println("Would you like to add a friend? (Say Y or N)"); 
       String reply = input.nextLine();
       if(reply.equals("Y"))
       {
        System.out.println("What is the name of your friend?");
        String name = input.nextLine();
        System.out.println("What is the age of your friend?");
        int age = input.nextInt();
        Friend newFriend = new Friend(name,age);
        addressBook.add("Name: " + newFriend.name + "; " + "Age: " + newFriend.age);
         Comparator<CustomObject> comparator = new Comparator<CustomObject>() {
           public int compare(CustomObject c1, CustomObject c2) {
               return c2.getAge() - c1.getAge(); // use your logic
              }


       Collections.sort(addressBook,comparator);
        System.out.println("This is your Address Book so far: " + addressBook);
        n++;
    }     
      ...
}

＆＃13;

Answer 2

实现比较器，然后调用

Collections.sort(addressBook, yourComparator);

如何对用户定义对象的链接列表进行排序？

2 个答案: