Question

我已经使自己成为一个非常基本的应用程序，可以计算你的水龙头并为每个水龙头提供一个很好的“ping”。我想要帮助的是在某些地标上你得到一个不同的声音，有点像用户做得好。我该怎么做才能使每100的倍数发出与往常不同的声音？

import UIKit
import AVFoundation

class ViewController: UIViewController {

@IBOutlet weak var background1: UIImageView!
@IBOutlet weak var counterLabel: UILabel!

@IBOutlet weak var button: UIButton!

var tapSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("schwing", ofType: "mp3")!)
var audioPlayer = AVAudioPlayer()

 var playerScoreTotal = 0

override func viewDidLoad() {
    super.viewDidLoad()
    audioPlayer = AVAudioPlayer(contentsOfURL: tapSound, error: nil)
    audioPlayer.prepareToPlay()
    // Do any additional setup after loading the view, typically from a nib.

}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

@IBAction func screenTapped(sender: AnyObject) {

    audioPlayer.play()


        playerScoreTotal += 1
    self.counterLabel.text = String(playerScoreTotal)
 self.counterLabel.textColor = UIColor.redColor()

    self.button.setTitle("", forState: UIControlState.Normal)
    }

}

Answer 1

您可以使用不同的声音创建第二个音频播放器。

然后您可以将此检查添加到您的函数中：

if ((playerScoreTotal % 100) != 0){
//Play the original sound
}
else{
//Play the **second** sound, do other stuff
}
//Do your other updates here

更改声音以匹配不同的倍数

1 个答案: