Question

这个AViewController是用Swift编写的。现在在我的Obj C管理器类中，我想检查viewcontroller的类型。但它没有读取，因为Obj C将类名称读为“ProjectName.AViewController”。我们怎样才能进行下面提到的检查？

//Swift class
class AViewController: UIViewController {
}

//Obj C - Manager class
- (void)sampleMethod:(UIViewController *)viewController {
 if ([viewController isKindOfClass:[AViewController class]]) {
  //Action
 }
}

Answer 1

在Swift中的类名前添加@objc(...Name...)。

例如：迅速

//Swift class
@objc(SwiftAViewController)
class AViewController: UIViewController {
}

例如：ObjC

//Obj C - Manager class
- (void)sampleMethod:(UIViewController *)viewController {
 if ([viewController isKindOfClass:[SwiftAViewController class]]) {
  //Action
 }
}

更多详情：Name of Swift class when exposed to Objective-C code does not respect the @objc renaming

Answer 2

由于swift中的错误，@ Freeerunner答案将无效。作为解决方法，我们可以将类名称作为字符串，然后进行字符串匹配。

if ([NSStringFromClass([AViewController class] isEqualToString:@"ProjectName.AViewController"]) {

}

Answer 3

let arrControllers = self.navigationController.viewControllers

                    for (indx, vc) in (arrControllers?.enumerated())! {
                        if vc is YourViewController{
                            self.navigationController.viewControllers.remove(at: indx)
                        }
                    }

Answer 4

您可以使用以下代码：

for viewController in viewControllers {
                            if viewController.isKind(of: OurViewController.self){
                                print("yes it is OurViewController")
                                self.navigationController?.popToViewController(viewController, animated: true)
                            }
                        }

有关详细信息，请参阅此答案already answered question

isKindOfClass方法检查Objective C中的Swift ViewController

4 个答案: