我试图用蟒蛇中的乌龟使用蒙特卡罗来近似pi。代码运行良好,但我遇到了问题,我的近似值和#34;都是非常错误的。我'总是得到小于1的值所以???我的代码在下面
import turtle
import math
import random
fred = turtle.Turtle()
fred.speed(0)
fred.up()
wn = turtle.Screen()
wn.setworldcoordinates(-1,-1,1,1)
numdarts = int(input("How many darts will you throw"))
for i in range(numdarts):
x = random.random()
y = random.random()
numIncircle = 0
if i == 0 or i == 1:
fred.up()
fred.goto(x, y)
if fred.distance(0, 0) <= 1:
numIncircle += 1
fred.color("Indianred")
fred.stamp()
fred.up()
else:
numIncircle += 0
fred.color("cyan")
fred.stamp()
fred.up()
else:
fred.goto(x, y)
if fred.distance(0, 0) <= 1:
numIncircle += 1
fred.color("Indianred")
fred.stamp()
fred.up()
else:
numIncircle += 0
fred.color("cyan")
fred.stamp()
fred.up()
piapproximation = float(float(numIncircle) / float(numdarts)) * 4
print piapproximation
wn.exitonclick()
答案 0 :(得分:0)
您在numIncircle = 0
循环内设置for
,实际上每次都会丢失计数。
偶尔它会计算最后一个,所以近似值为1 /飞镖数* 4.这将以频率pi / 4 ≈ 0.78539816339发生。
这是我的建议:
import turtle
import math
import random
fred = turtle.Turtle()
fred.speed(0)
fred.up()
wn = turtle.Screen()
wn.setworldcoordinates(-1,-1,1,1)
numdarts = int(input("How many darts will you throw"))
// this MUST come before the for loop
numIncircle = 0
for i in range(numdarts):
x = random.random() * 2 - 1
y = random.random() * 2 - 1
if i == 0 or i == 1:
fred.up()
fred.goto(x, y)
if fred.distance(0, 0) <= 1:
numIncircle += 1
fred.color("Indianred")
fred.stamp()
fred.up()
else:
numIncircle += 0
fred.color("cyan")
fred.stamp()
fred.up()
else:
fred.goto(x, y)
if fred.distance(0, 0) <= 1:
numIncircle += 1
fred.color("Indianred")
fred.stamp()
fred.up()
else:
numIncircle += 0
fred.color("cyan")
fred.stamp()
fred.up()
piapproximation = float(float(numIncircle) / float(numdarts)) * 4
print piapproximation
wn.exitonclick()