Question

我试图找出这个，但是NSSet（array：x）.allObjects只适用于[Int]。

如何生成随机不可重复数组？

var x = map(1...5) { _ in arc4random_uniform(15)}
let xNonRepating = NSSet(array: x).allObjects
if x.count != xNonRepating.count {
    //do nothing
} else {
    x = map(1...5) { _ in arc4random_uniform(15)}
    println(x)
}

Answer 1

你的要求并不是很清楚。

如果您希望能够从没有重复的数组中获取对象，请使用以下内容：

var seedArray = ["one", "two", "three", "four", "five"]
var randomArray = Array()


func randomString -> String
{
  if randomArray.count = 0
  {
    randomArray += seedArray
  }
  return randomArray.removeAtIndex(arc4random_uniform(randomArray.count))
}

您可以调整上述方法来保存任何类型对象的数组，或将其更改为通用对象，以便您可以管理任何类型对象的数组。

Answer 2

首先，您必须将arc4random_uniform的结果转换为Int：

var draw = map(1...5) { _ in Int(arc4random_uniform(15))}

然后，您需要创建一个while循环，只有在NSSet数组中包含的唯一元素数小于绘制计数时才会执行。

var badDrawCounter = 0
while NSSet(array: draw).count < draw.count {
    //it will only enter here if there was a repeated number in your draw
    badDrawCounter++
    println("bad draw = \(draw)")
    // lets draw it again and if the result is not ok it will stay looping until you get a good draw (no repeating numbers)
    draw = map(1...5) { _ in Int(arc4random_uniform(15))}
}

println(draw)

在SWIFT中生成随机不可重复的数组

2 个答案: