Question

我有一个使用Spray Routing的现有Spray应用程序，我最近添加了一个文件流上传Actor based on the example。

我能解释的是如何将我现有的根HttpService actor与不扩展HttpService的文件上传Actor结合起来。

我现有的root服务actor看起来像这样：

class RootService extends Actor with HttpService with Routes with ActorLogging {
  def receive = runRoute {
      routes
  }
}

我的文件上传了这样的Actor：

class FileUploadService extends Actor with Logging {
  def receive = {
    case part @ HttpRequest(POST, Uri.Path("/upload"), headers, entity: HttpEntity.NonEmpty, protocol) => {
      val parts = part.asPartStream()
      val client = sender
      val handler = context.actorOf(Props(new FileUploadHandler(client, parts.head.asInstanceOf[ChunkedRequestStart])))
      parts.tail.foreach(handler !)
    }
    case start @ ChunkedRequestStart(HttpRequest(POST, Uri.Path("/upload"), _, _, _)) => {
      val client = sender
      val handler = context.actorOf(Props(new FileUploadHandler(client, start)))
      sender ! RegisterChunkHandler(handler)
    }
  }
}

我尝试修改我的root服务actor，如下所示：

class RootService extends Actor with HttpService with Routes with ActorLogging {
  val fileUploadActor = context.actorOf(Props[FileUploadService], "fileUploadActor")
  def receive = runRoute {
    pathPrefix("upload") {
        fileUploadActor ! _.request
    } ~ {
      route
    }
  }
}

但这不能正常工作。最终，响应永远不会回到客户端（即使我指定ask vs tell）。

有关工作实施的任何建议吗？

谢谢！

Answer 1

在RootService中，将RequestContext发送给上传actor：

def receive = runRoute {
 pathPrefix("upload") {
   ctx => fileUploadActor ! ctx
 }
}

然后在文件上传服务中，您可以像RootService一样使用runRoute，并在该服务中完成请求。如果您有对RequestContext的引用，则无需回复RootService。

使用文件上传Actor进行喷涂路由

1 个答案: