Unicode渲染（更新）

Question

我几天前发布了我的问题，而我还在处理我的代码。我将重申我的问题，以便每个人都清楚。

目标：使用循环打印所有可用的Unicodes。

问题：为什么我只能将它们作为符号打印出来，如果它们是用字符串硬编码而不是变量。

输出：

U000000

U000001

U000002

...

U000017

U000018

---

    #include <iostream>
    #include <cmath>
    using namespace std;
    const int HexBase=16;
    const int HexMax=15;
    const int UniCharMaxPrint=1000;
    const int ASCCIAlphaCapBase=48;

    int main() {

        int DecNum = 0;
        int sizeHex= 3;

        for (int j=0; j < UniCharMaxPrint; j++)//prints 100 unviersal Chars
        {
            int DecNumCopy = DecNum;
            int resultDiv =0;
            string HexChar=" ";
            string HexNum ="X";
            string UniNum ="u";
            string BackSlash = "\\";
            string full="HI ";
            for (int i = sizeHex; i >=0; i--)
            {

                //Dec calcultion
                resultDiv = (DecNumCopy/(int)(pow(HexBase,i)));
                DecNumCopy = DecNumCopy - ((int)(pow(HexBase,i)) * resultDiv);
                if ((i==0) && (resultDiv>HexMax)){cout <<"Error # is Too large"<<endl;}//Check if the number entered is big or not

                //Get the equivalente Hex charcter
                if ((resultDiv >= 0)&&(resultDiv <= 9))
                { HexChar = ASCCIAlphaCapBase + resultDiv;}
                else if ((resultDiv >= 10)&&(resultDiv <= 15))
                {   switch (resultDiv)
                    {   case 10 : {HexChar='a'; break;};
                        case 11 : {HexChar='b'; break;};
                        case 12 : {HexChar='c'; break;};
                        case 13 : {HexChar='d'; break;};
                        case 14 : {HexChar='e'; break;};
                        case 15 : {HexChar='f'; break;};
                    }
                }
                else {HexChar='*';};


                //if(i==sizeHex){full.append(UniNum);};


                //Add to the result string
                //HexNum.append(HexChar);
                UniNum.append(HexChar);
                full = BackSlash+UniNum;
            }//endfor
            DecNum++;
            cout<< full << endl;
        }
        return 0;
    }