填充结构的数据,该结构包含指向不同结构的指针数组

时间:2015-04-02 02:05:08

标签: c struct

在下面的代码中有两个结构。一个名为person的人和一个名为person_list的人名单,该名单通过引用来保存人员结构或“人物”的列表。

我想在person_list中填写(或引用)10个人结构,但是在运行此代码时,我遇到了分段错误。我如何处理或声明每个人的记忆,这样才有效?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_LENGTH 50
#define MAX_PEOPLE_ALLOWED 10

struct person_list {
    struct person *people[MAX_PEOPLE_ALLOWED];
};

struct person
{
    char name[MAX_LENGTH];
    //int age;
};

int main(int argc, char *argv)
{
    struct person_list list;
    struct person pers[10];
    int i;
    char name[MAX_LENGTH];

    for (i = 0; i < MAX_PEOPLE_ALLOWED; i++) {
        sprintf(descrip, "I am person number: %d", i);
        strcpy( &pers[i].name, name);
        list.people[i] = &pers[i];
    }
}

1 个答案:

答案 0 :(得分:0)

@BDillan,我对你的代码做了一些简单的修正,希望你正在寻找类似的东西

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_LENGTH 50
#define MAX_PEOPLE_ALLOWED 10

struct person_list {
struct person *people[MAX_PEOPLE_ALLOWED];
};

struct person
{
char name[MAX_LENGTH];
//int age;
};

int main()
{

struct person_list list;
struct person pers[10];
char descrip[MAX_LENGTH];
int i;
char name[MAX_LENGTH];

for (i = 0;i < MAX_PEOPLE_ALLOWED; i++)
 {
    sprintf(descrip, "I am person number: %d", i);
    strcpy(pers[i].name,descrip);
 //puts(pers[i].name);
   list.people[i] = &pers[i];
 }

 //to display the details of persions entered above

 for (i = 0;i < MAX_PEOPLE_ALLOWED; i++)
             printf("%s \n",list.people[i]->name);

 }