指向结构体中的结构体的指针

Question

所以我有文件country.c：

struct City{
    char* name;
    char* food;
    int population;

};

struct Country{
    char *name;
    int numCities;
    pCity cities;
    pTerritory countryTerr;

};

struct Territory{
    int x1;
    int x2;
    int y1;
    int y2;
};
typedef struct City* pCity;
typedef struct Country* pCountry;
typedef struct Territory* pTerritory;

void deleteCountry(pCountry country){
    if(country != NULL){
        int num_of_cities = country->numCities;
        for(int i = 0 ; i<num_of_cities; i++){
            if (country->cities){
                    free(country->cities[i].food);
                    free(country->cities[i].name);
                    free(country->cities[i]);
                }
            }

        }
        free(country->cities);
        free(country->name);
        free(country->countryTerr);
        free(country);
    }
}
pCity citySetter(pCity new_city, char* name, char* food,int popolution){

    new_city = (pCity)malloc(sizeof(*new_city));
    new_city->name = (char*)malloc((strlen(name)+1)*sizeof(char));
    new_city->food = (char*)malloc((strlen(food)+1)*sizeof(char));
    if (new_city->name)
        strcpy(new_city->name,name);
    if(new_city->food)
        strcpy(new_city->food,food);
    new_city->population = popolution;
    return new_city;
}
status addCity(pCountry country,pCity city){
    if (country==NULL || city==NULL)
        return failure;

    if(country->numCities==0)
        country->cities = (pCity)malloc(sizeof(struct City));
    else
        country->cities =(pCity)realloc(country->cities,(country->numCities+1)*sizeof(struct City));

    if(!country->cities)
            return failure;

    country->cities[country->numCities] = *city;
    country->numCities++;
    return success;
}

现在为了将城市添加到国家/地区，我首先使用“ citySetter”，然后使用

“ addCity”，在程序结尾，我称为“ deleteCountry”。

我正在使用valgrind来检测内存泄漏，并且它通知我我没有

释放我在“ citySetter”中创建的城市，因此我想删除每个城市

在城市数组中使用

struct：

free(country->cities[i]);

但是我得到了编译错误，因为我指的是结构本身而不是

指针，如何访问数组中每个城市结构的地址

要释放它？