Question

我想要做的是将PHP字符串拆分为一组子字符串，这些字符串根据开始这些子字符串的“divider”字符分组为数组。字符*，^和%保留为分隔符。因此，如果我有字符串"*Here's some text^that is meant*to be separated^based on where%the divider characters^are"，它应该被拆分并放在如下的数组中：

array(2) {
    [0] => "*Here's some text"
    [1] => "*to be separated"
}

array(3) {
    [0] => "^that is meant"
    [1] => "^based on where"
    [2] => "^are"
}

array(1) {
    [0] => "%the divider characters" 
}

我完全失去了这个。有谁知道如何实现这个？

Answer 1

如果您愿意，请不要问$matches[0]如此取消设置：

preg_match_all('/(\*[^*^%]+)|(\^[^*^%]+)|(%[^*^%]+)/', $string, $matches);
$matches = array_map('array_filter', $matches);

print_r($matches);

array_filter()从捕获组子数组中移除空白以提供问题中显示的数组

将PHP字符串分成基于＆＃34; divider＆＃34;的排列子字符串。人物

1 个答案: