如何将选定的userId传递给动作类?

时间:2015-03-31 12:00:01

标签: jsp liferay liferay-6 portlet liferay-theme

我创建了一个portlet,我以编程方式添加用户。我现在可以添加和查看用户。为了编辑我创建的用户<liferay-ui:icon-menu>并添加了两个选项(编辑和取消激活)。现在,在单击或选择相应的用户操作按钮(编辑/取消激活)时,我需要将所选的用户ID发送到我的操作类。一旦我在动作类中获得了userID,我将使用更新的值调用UserLocalServiceUtil.updateUser()方法。任何人都可以告诉我如何将选定的用户ID发送到我的动作类。

我的代码如下,

view.jsp的

<liferay-ui:search-container delta="10" emptyResultsMessage="no-users-were-found">
        <liferay-ui:search-container-results
                results="<%=UserLocalServiceUtil.getUsers(searchContainer.getStart(), searchContainer.getEnd())%>"
        total="<%=UserLocalServiceUtil.getUsersCount()%>" />
        <liferay-ui:search-container-row className="com.liferay.portal.model.User" keyProperty="userId"        modelVar="user">

                <liferay-ui:search-container-column-text name="name" value="<%= user.getFullName() %>"/>
                <liferay-ui:search-container-column-text name="first-name" property="firstName"        />
                <liferay-ui:search-container-column-text name="last-name" property="lastName" />
                <liferay-ui:search-container-column-text name="screen-name"        property="screenName"/>
                <liferay-ui:search-container-column-jsp align="right" path="/html/users/custom_user_actions.jsp" />

        </liferay-ui:search-container-row>
        <liferay-ui:search-iterator />
</liferay-ui:search-container>
<liferay-ui:search-container delta="10" emptyResultsMessage="no-users-were-found" />

custom_user_actions.jsp

<liferay-ui:icon-menu>  
  <portlet:actionURL name="edit" var="edit">
          <portletaram name="action" value="edit" />
  </portlet:actionURL>
  <liferay-ui:icon image="edit" message="Edit" url="<%=edit.toString() %>" />

  <portlet:actionURL name="deactivate" var="deactivate">
          <portletaram name="action" value="deactivate" />
  </portlet:actionURL>
  <liferay-ui:icon image="deactivate" message="deactivate" url="<%= deactivate.toString() %>" />
</liferay-ui:icon-menu>

动作类

public void edit(ActionRequest request, ActionResponse response) throws com.liferay.portal.kernel.exception.PortalException, com.liferay.portal.kernel.exception.SystemException{
                  System.out.println("<<<< Controller add() method has been called >>>>>>>>>");

          }


        public void deactivate(ActionRequest request, ActionResponse response) throws com.liferay.portal.kernel.exception.PortalException, com.liferay.portal.kernel.exception.SystemException{
                  System.out.println("<<<< Controller delete() method has been called >>>>>>>>>");

          }

任何人都可以建议我如何将选定的行用户ID传递给我的动作类。

提前致谢。

1 个答案:

答案 0 :(得分:2)

custom_user_actions.jsp中获取相应的userId,并将其作为参数传递给您的操作类。

custom_user_actions.jsp

中添加以下代码
<%
 ResultRow resultRow = (ResultRow)request.getAttribute(WebKeys.SEARCH_CONTAINER_RESULT_ROW);
 User userObj = (User)resultRow.getObject();
 %>

并按如下方式传递参数,

<portlet:actionURL name="edit" var="edit">
          <portletaram name="selectedId" value="<%String.valueOf(user.getUserId())%>" />
  </portlet:actionURL>
  <liferay-ui:icon image="edit" message="Edit" url="<%=edit.toString() %>" />

获取动作类中的参数,

public void edit(ActionRequest request, ActionResponse response) throws com.liferay.portal.kernel.exception.PortalException, com.liferay.portal.kernel.exception.SystemException{

String usrID = ParamUtil.getString(request, "selectedId")
                  System.out.println("<<<< Controller add() method has been called >>>>>>>>>");

          }

希望它可以帮助你:)