Question

我连接到一个对其有查询的PHP文件。现在我需要知道如何检索de user ID Session并将其传递给PHP进行查询，并且只显示登录用户的表数据。

Config.java（我开始做共享首选项的地方）

//Keys for email and password as defined in our $_POST['key'] in login.php
public static final String KEY_EMAIL = "email";
public static final String KEY_PASSWORD = "password";
public static final String KEY_ID = "id_utilizador";


//If server response is equal to this that means login is successful
public static final String LOGIN_SUCCESS = "success";

//Keys for Sharedpreferences
//This would be the name of our shared preferences
public static final String SHARED_PREF_NAME = "myloginapp";

//This would be used to store the email of current logged in user
public static final String EMAIL_SHARED_PREF = "email";

//This would be used to store the id of current logged in user
public static final String ID_SHARED_PREF = "id_utilizador";

//We will use this to store the boolean in sharedpreference to track user is loggedin or not
public static final String LOGGEDIN_SHARED_PREF = "loggedin";

登录的PHP文件

<?php 

    if($_SERVER['REQUEST_METHOD']=='POST'){
        //Getting values 
        $email = $_POST['email'];
        $password = $_POST['password'];
        $id = $_POST['id_utilizador'];

        //Creating sql query
        $sql = "SELECT * FROM Utilizadores WHERE email='$email' AND password='$password'";

        //importing dbConnect.php script 
        require_once('connection.php');

        //executing query
        $result = mysqli_query($con,$sql);

        //fetching result
        $check = mysqli_fetch_array($result);

        //if we got some result 
        if(isset($check)){
            //displaying success 
            echo "success";
        }else{
            //displaying failure
            echo "failure";
        }
        mysqli_close($con);
    }

包含我想要使用的查询的PHP文件（我希望为特定会话userId付出代价。

<?php
class Historico {

    private $db;
    private $connection;

    function __construct() {
        $this ->db = new DB_Connection();
        $this ->connection = $this->db->getConnection();
    }

    public function guardar_historico($custos){
        $query = "insert into Custoss (custos) values ( '$custos')";
        $inserted = mysqli_query($this -> connection, $query);
        if($inserted == 1 ){
            $json['success'] = 'Custos guardado';
        }else{
            $json['error'] = 'Custos nao guardado';
        }
        echo json_encode($json);
        mysqli_close($this->connection);
    }

}


$historico = new Historico();
if(isset($_POST['custos'])) {
    $custos = $_POST['custos'];

    if(!empty($custos)){
        $historico-> guardar_historico($custos);

    }else{
        echo json_encode("you must type both inputs");
    }

}
?>

如何检索UserID将其传递给SharedPreferences？

0 个答案: