Question

文件：/// C：/用户/克里斯/下载/ lab04_guessinggame％20（6）.PDF *代码不会输出最后一个方法

import java.util.*;

public class GuessingGame{
    public static void main( String[] args ){
        int x=getRandomNumber();
        int y=getGuessFromUser(x);
        int v=getGuessFromUser(x);
    }

    public static int getRandomNumber(){
        return (int)(Math.random()*26);
    }

    public static int getGuessFromUser(int x){
        Scanner keyboard = new Scanner(System.in);
        int y;
        int v=0;
        do{
            System.out.print("Enter a number between 1 and 25: ");
            y=keyboard.nextInt();
            v++;
        } while(y<=0||y>25 || v<5);
        return y;
    }

    public static void main(int x, int y, int v){
        do{
            if(x>y)
                System.out.println("TOO LOW");
            if(x<y)
                System.out.println("TOO HIGH");
            if(x==y)
                System.out.print("YOU ARE CORRECT! IT TOOK YOU " + v + " GUESSES!");
        }while(v<5);
    }
}

主要方法不会输出

Answer 1

尝试这样的事情：

public class GuessingGame{
    public static void main( String[] args ){
        int x=getRandomNumber();
        int y=getGuessFromUser(x);
        int v=getGuessFromUser(x);
        output(x,y,v);
    }

    public static int getRandomNumber(){
        return (int)(Math.random()*26);
    }

    public static int getGuessFromUser(int x){
        Scanner keyboard = new Scanner(System.in);
        int y;
        int v=0;
        do {
            System.out.print("Enter a number between 1 and 25: ");
            y=keyboard.nextInt();
            v++;
        } while(y<=0||y>25 || v<5);
        return y;
    }

    public static void output(int x, int y, int v){
        do {
            if (x>y)
                System.out.println("TOO LOW");
            if (x<y)
                System.out.println("TOO HIGH");
            if (x==y)
                System.out.print("YOU ARE CORRECT! IT TOOK YOU " + v + " GUESSES!");
        } while (v<5);
    }
}

正如人们在评论中所说，你不能有两种主要方法，所以你必须重命名最后一种，然后在某处调用它。话虽如此，我只是修改了你的代码，但你可能想要更多地思考它的结构。

Answer 2

我不知道你想通过这个代码实现什么，但关于

主要方法不会输出

就我所见，您的代码中存在2个问题

你打电话给main(int,int,int)。
在main(int,int,int)中，您有一个无限循环，因为V永远不会改变。

所以代码是

import java.util.*;

public class GuessingGame{
public static void main( String[] args ){
int x=getRandomNumber();
int y=getGuessFromUser(x);
int v=getGuessFromUser(x);
main(x, y,v);
}


public static int getRandomNumber(){
return (int)(Math.random()*26);
}
public static int getGuessFromUser(int x){
Scanner keyboard = new Scanner(System.in);
int y;
int v=0;
do{
System.out.print("Enter a number between 1 and 25: ");
y=keyboard.nextInt();
v++;
}while(y<=0||y>25 || v<5);
return y;
}
public static void main(int x, int y, int v){
do{
if(x>y)
System.out.println("TOO LOW");
if(x<y)
System.out.println("TOO HIGH");
if(x==y)
System.out.print("YOU ARE CORRECT! IT TOOK YOU " + v + " GUESSES!");
}while(v++<5);
}
}

Answer 3

这应该改变：

public static void main(int x, int y, int v){
do{
if(x>y)
System.out.println("TOO LOW");
if(x<y)
System.out.println("TOO HIGH");
if(x==y)
System.out.print("YOU ARE CORRECT! IT TOOK YOU " + v + " GUESSES!");
}while(v<5);
}

为：

public static void checkGuess(int randomNumber, int tries){
    do{
        int guess = getGuessFromUser(randomNumber);
        tries++;

        if(randomNumber > guess) System.out.println("TOO LOW");

        if(randomNumber < guess) System.out.println("TOO HIGH");

        if(randomNumber == guess) 
        System.out.print("YOU ARE CORRECT! IT TOOK YOU " + tries + " GUESSES!");
    }while(tries < 5);
}

对main的更改：

public static void main( String[] args ){
    int x=getRandomNumber();
    int v = 0;
    checkGuess(x, v);
}

对getGuessFromUser的更改：

public static int getGuessFromUser(int x){
    Scanner keyboard = new Scanner(System.in);
    int y;

    do{
        System.out.print("Enter a number between 1 and " + x + ": ");
        y=keyboard.nextInt();

    }while(y <= 0 || y > x);

    return y;
}

代码中存在许多逻辑和语法问题。我建议您在代码中一步一步地思考它的作用。另外，不要忘记仔细检查变量的范围。

为什么java输出我的最后一个方法

3 个答案: