Question

我有一个字符串模式，如列“备注”：

remarks
pay mode: called to pay
pay mode: cash
pay mode: bank deposit
pay mode: from third party

我必须在pay mode:之后选择所有字符串。一种方法是在第一次出现:值后检索所有字符串，或者从左边的9个字符后选择左边的所有字符串。

如何在SQL Server中执行此操作？

Answer 1

一种方法是使用Substring + Charindex

SELECT Substring('pay mode: called to pay', Charindex(':', 'pay mode: called to pay')
                                                + 1, Len('pay mode: called to pay'))

或使用Right + Charindex

SELECT RIGHT('pay mode: called to pay', Len('pay mode: called to pay') -
                                             Charindex(':', 'pay mode: called to pay'))

Answer 2

检查一下并希望它可以帮助你

Create table #table1
(
Remarks varchar(100)
)

Insert into #table1 values('pay mode: called to pay'),
('pay mode: cash'),
('pay mode: bank deposit'),
('pay mode: from third party')


Select substring(Remarks,11,len(Remarks)) from #table1

更好的方法是，您也可以使用CHARINDEX。检查此查询：

Select SUBSTRING(Remarks, CHARINDEX(':',Remarks)+1, len(Remarks)) from #table1

Answer 3

我会使用case来确保字符串采用预期格式：

select (case when remarks like 'pay mode: %'
             then stuff(remarks, 1, 10, '')
             else remarks
        end)

或者，也许是一个更通用的解决方案：

select (case when remarks like '%: %'
             then stuff(remarks, 1, charindex(': ', remarks)+1, '')
             else remarks
        end)

编辑：

正如Firebird指出的那样，使用case时不需要stuff()。这使得这个解决方案对于冒号更加优雅。当没有匹配时，charindex()返回0，因此在这种情况下没有任何反应。你可以这样做：

select stuff(remarks, 1, charindex(':', remarks), '')

但是，要在之后捕获空间，需要使用case()或ltrim()。

Answer 4

选择修剪（备注，＆＃39;付费模式：＆＃39;，＆＃39;＆＃39;）备注 FROM TableName

Answer 5

为了在字符串的基础上进行拆分，请将其用作SQL Server函数。将sql server函数定义为

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER FUNCTION [dbo].[split](
          @delimited NVARCHAR(MAX),
          @delimiter NVARCHAR(100)
        ) RETURNS @t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX))
        AS
        BEGIN
          DECLARE @xml XML
          SET @xml = N'<t>' + REPLACE(@delimited,@delimiter,'</t><t>') + '</t>'

          INSERT INTO @t(val)
          SELECT  r.value('.','varchar(MAX)') as item
          FROM  @xml.nodes('/t') as records(r)
          RETURN
END

您可以将此功能称为dbo.split('pay mode: called to pay', 'pay mode:')

获取SQL Server中某些字符或特定字符后的字符串

5 个答案: