Question

考虑一个字符串有多个点，但我想从第5个点（。）到字符串的末尾读取和显示。您可以建议任何单个选择查询。例如：
I / P

We.are.inserting.a.lot.of.records by using SSIS Package.even.the.records are.not committed.

o / P

of.records by using SSIS Package.even.the.records are.not committed.

Answer 1

使用CHARINDEX，一种方法：

DECLARE @String varchar(500);
SET @String = 'We.are.inserting.a.lot.of.records by using SSIS Package.even.the.records are.not committed.';

SELECT STUFF(@string, 1, CI5.CI,'')
FROM (VALUES(CHARINDEX('.',@String))) CI1(CI)
     CROSS APPLY (VALUES(CHARINDEX('.',@String, CI1.CI+1))) CI2(CI)
     CROSS APPLY (VALUES(CHARINDEX('.',@String, CI2.CI+1))) CI3(CI)
     CROSS APPLY (VALUES(CHARINDEX('.',@String, CI3.CI+1))) CI4(CI)
     CROSS APPLY (VALUES(CHARINDEX('.',@String, CI4.CI+1))) CI5(CI);

返回：'of.records by using SSIS Package.even.the.records are.not committed.'

Answer 2

您可以拨打recursice CTE进行救援：

DECLARE @yourString NVARCHAR(MAX)='We.are.inserting.a.lot.of.records by using SSIS Package.even.the.records are.not committed.';
DECLARE @CountDots INT=5;

WITH recCTE AS
(
    SELECT @yourString AS Original
          ,CHARINDEX('.',@yourString) AS PosDot
          ,1 AS DotCount
    UNION ALL

    SELECT r.Original
          ,CHARINDEX('.',@yourString,r.PosDot+1)
          ,r.DotCount+1
    FROM recCTE AS r
    WHERE r.DotCount<@CountDots
)
SELECT SUBSTRING(@yourString,(SELECT MAX(PosDot) FROM recCTE)+1,LEN(@yourString))

一个优点是您可以动态定义点数。另一个优点是您可以将其完全内联到任何查询，VIEW或iTVF。

更新：基于集合的方法

DECLARE @yourStringTable TABLE(ID INT IDENTITY,SomeString NVARCHAR(MAX));
INSERT INTO @yourStringTable VALUES 
 ('We.are.inserting.a.lot.of.records by using SSIS Package.even.the.records are.not committed.')
,('1.2.3.4.5.6.7.8');
DECLARE @CountDots INT=5;

WITH recCTE AS
(
    SELECT ID
          ,SomeString AS Original
          ,CHARINDEX('.',SomeString) AS PosDot
          ,1 AS DotCount
    FROM @yourStringTable
    UNION ALL

    SELECT r.ID
          ,r.Original
          ,CHARINDEX('.',r.Original,r.PosDot+1)
          ,r.DotCount+1
    FROM recCTE AS r
    WHERE r.DotCount<@CountDots
)
SELECT ID
      ,Original
      ,SUBSTRING(Original,(SELECT MAX(x.posDot) FROM recCTE AS x WHERE x.ID=recCTE.ID)+1,LEN(Original))
FROM recCTE
WHERE PosDot=(SELECT MAX(x.posDot) FROM recCTE AS x WHERE x.ID=recCTE.ID)

Answer 3

嵌套CHARINDEX：

SELECT 
  STUFF(val,1, charindex('.',val,charindex('.',val,charindex('.',val,charindex('.',
   val,charindex('.',val)+1)+1)+1)+1), '')
FROM (values('.2.3.4.5.6.7'),('2.3.4.5.6.7'),('abc')) x(val)

当字符串不包含5个点时，这将返回整个字符串。

Answer 4

对于上述字符串值，只有patindex()函数足以在dot(.)s substring()函数<{1}}之后读取字符串

select 
        substring(I/P, patindex('%[.A-Z].[A-Z][.A-Z].[A-Z]%', I/P)+2, LEN(I/P)) [O/P]
from table

在特定字符后显示字符串

4 个答案:

更新：基于集合的方法