Question

我使用microsoft word（查找和替换）解决了python挑战＃2但是当我使用python时，我失败了，因为这段代码不起作用......

with open("C:\\Python34\\Python Challenge\\Q2\\Q2.txt") as f: 
    f = str(f)
    f = str.replace(f, '!','')
    f = str.replace(f, '@','')
    f = str.replace(f, '#','')
    f = str.replace(f, '$','')
    f = str.replace(f, '%','')
    f = str.replace(f, '^','')
    f = str.replace(f, '&','')
    f = str.replace(f, '*','')
    f = str.replace(f, '(','')
    f = str.replace(f, ')','')
    print(f)

研究：它将打印出该文件的属性。为什么不提供信息？而且，我怎么能改变它？我试过f.open()和＆＃34; f＆＃34;。我已经在这几个小时内多次更改了代码（我认为是3），但是这段代码仍然无效。

Answer 1

您需要使用f = f.read()：

f = str(f)将显示文件对象的字符串表示形式，如：

 <open file 'C:\\Python34\\Python Challenge\\Q2\\Q2.txt"', mode 'r' at 0x7f76a5a26e40>

然后使用str.translate删除字符：

with open("C:\\Python34\\Python Challenge\\Q2\\Q2.txt") as f: 
    f = f.read()
    f = f.translate(None,"!@#$%&()*^")
    print(f)

对于python 3，我们需要使用要替换的字符的ord创建一个dict映射，并将其传递给translate：

with  open("C:\\Python34\\Python Challenge\\Q2\\Q2.txt")  as f:
    f = f.read()
    # {ord(ch):"" for ch in "!@#$%&()*^"}
    f = f.translate({64: '', 33: '', 35: '', 36: '', 37: '', 38: '', 40: '', 41: '', 42: '', 94: ''})
    print(f)

Answer 2

如果您说f = str(f) 正在阅读 f，那么您将获得文件对象。准确地说是一串。然后你要替换它没有的字符，并将其打印出来。

您需要让f成为文件的内容：

with open("PythonChallenge2.txt") as f: 
    f = str(f.readlines())  ##<-- Changed this to actually set f to the file contents, not the file object
    f = str.replace(f, '!','')
    f = str.replace(f, '@','')
    f = str.replace(f, '#','')
    f = str.replace(f, '$','')
    f = str.replace(f, '%','')
    f = str.replace(f, '^','')
    f = str.replace(f, '&','')
    f = str.replace(f, '*','')
    f = str.replace(f, '(','')
    f = str.replace(f, ')','')
    print(f)

添加：

f = str.replace(f, '[','')
f = str.replace(f, ']','')
f = str.replace(f, '{','')
f = str.replace(f, '}','')
f = str.replace(f, '+','')
f = str.replace(f, '_','')
f = str.replace(f, '\\n','')

给你一个几乎显而易见的答案。

Answer 3

因为这里没有人提到re解决方案

  with open("C:\\Python34\\Python Challenge\\Q2\\Q2.txt") as f: 
      print re.sub("!@#$%&()*^","",f.read())

Answer 4

您可以使用搜索创建字典并替换字符串。

然后搜索并替换该项目中的每个项目。

replace_dict = {'!':'', '@':'', '#':'', '$':'', '%':'', '^':'', '&':'', '*':'', '(':'', ')':''}

with open("C:\\Python34\\Python Challenge\\Q2\\Q2.txt") as f: 
    content = f.read() 
    print content         # <---print the original content
    for key,  value in replace_dict.items():
        content = content.replace(key, value)
    print content         # <---print the modified content

Python挑战＃2消除

4 个答案: