Question

根据documentation CFDictionaryCreate用于在swift中实例化CFDictionary。

func CFDictionaryCreate(_ allocator: CFAllocator!,
                  _ keys: UnsafeMutablePointer<UnsafePointer<Void>>,
                  _ values: UnsafeMutablePointer<UnsafePointer<Void>>,
                  _ numValues: CFIndex,
                  _ keyCallBacks: UnsafePointer<CFDictionaryKeyCallBacks>,
                  _ valueCallBacks: UnsafePointer<CFDictionaryValueCallBacks>) -> CFDictionary!

如何创建keys和values参数？到目前为止，我已尝试使用swift的String类型，希望它会自动转换为适当的类型：

import Foundation

var keys : [String] = ["key1", "key2"]
var values : [String] = ["value1", "value2"]
var keyCallbacks = kCFTypeDictionaryKeyCallBacks
var valueCallbacks = kCFTypeDictionaryValueCallBacks
var dict : CFDictionary = CFDictionaryCreate(kCFAllocatorDefault,
    &keys, &values, 2, &keyCallbacks, &valueCallbacks)

很遗憾，我收到一条错误消息，指出String不是keys和values数组元素的正确类型：

main.swift:41:2: error: 'String' is not identical to 'UnsafePointer<Void>'
    &configKeys, &configValues, 3, &keyCallbacks, &valueCallbacks)

如何从UnsafePointer<Void>制作String？

Answer 1

对于Swift 3，您需要额外投射到CFDictionary。否则上下文类型＆＃39; CFDictionary＆＃39;不能与字典一起使用文字被抛出。

let options: CFDictionary = [kSecImportExportPassphrase as String : "certificateKey"] as CFDictionary

有关详情，请参阅https://bugs.swift.org/browse/SR-2388。

Answer 2

rintaro的评论适用于字符串文字，但不适用于我使用CFStringRef和Swift String的时候：

// Error: Contextual type 'CFDictionary' cannot be used with dictionary literal
let options: CFDictionary = [kSecImportExportPassphrase : "certificateKey"]

我必须将CFStringRef转换为Swift String：

let options: CFDictionary = [kSecImportExportPassphrase as String : "certificateKey"] // works

如何在OS X目标中创建CFDictionary？

2 个答案: