Question

我有点难过。我有一种感觉，我在代码中的某个地方出了问题，但似乎无法完全按照我的意思。基本上我被分配了一个C代码，据说可以模拟警用雷达枪。用户将插入一个整数，并且根据输入，将告知用户该输入是否会超速，并且如果是特定罚款将被给出。

以下是我的代码

/* *****

Author: Shivan Kamal
Date: 12-3-2015
Program Reason: To simulate a police speed radar by getting user to insert a number
        and to give them an answer to whether they are speed or not, and provide a warning or a fine
        where required.

*****/

#include <stdio.h>

int main()
{
    /***** 
    Declaring values
    ******/
    int speed;
    const int LIMIT1 = 60;
    const int LIMIT2 = 65;
    const int LIMIT3 = 70;
    const int LIMIT4 = 80;
    const int LIMIT5 = 200;

    const int FINE1 = 80;
    const int FINE2 = 150;
    const int FINE3 = 500;

    /*****
    Beginning of the program
    *****/

    printf(" If you want to check whether a certain speed issues you\n");
    printf(" a warning or a fine and how much, please input a number value\n");
    printf(" NOTE: the number value will be in KM/h.\n");
    scanf("%d%*c" , speed);

    if(speed == 0)
    {
        printf(" Your vehicle is not moving at '0'km/h. If your car was blocking traffic, you would be issued a fine. Please be careful.\n");
    }
    else 
        if(speed <0)
        {
            printf("Your vehicle is most likely in reverse. If this is the case and your vehicle disrupts traffic. You may be issued a fine. Please be careful.\n");
        }
        else
            if(speed <= LIMIT1)
            {
                printf("You're within the speed limit.\n");
            }
            else
                if(speed <= LIMIT2)
                {
                    printf("SPEEDING - Warning! You are going over the speed limit.\n Please slow down or you may be issued a fine");
                }
                else
                    if(speed <= LIMIT3)
                    {
                        printf("SPEEDING - You have gone over the speed limit.\n Fined $FINE1.\n");
                    }
                    else
                        if(speed <= LIMIT4)
                        {
                            printf("SPEEDING - You have gone over the speed limit.\n Fined $FINE2.\n");
                        }
                        else
                            if(speed <= LIMIT5)
                            {
                                printf("SPEEDING - You have gone over the speed limit.\n Fined $FINE3.\n");
                            }
                            else
                            {
                                printf(" By getting caught going faster than any limit higher than 20km/h.\n Your fine will simply keep getting bigger.\n");
                                printf("Please stick to the speed limit and follow the rules.\n");
                            }

return(0);
}

编译代码并运行代码时，无论用户输入什么内容，都会一遍又一遍地提供一条特定的消息。消息在屏幕截图中。

enter image description here

任何人都可以告诉我，我哪里出错了？

也正是如何在printf语句中打印常量变量。这是另外一部分，我认为我也做错了。

Answer 1

更改

scanf("%d%*c" , speed);

到

scanf("%d%*c" , &speed);

在接受&的值时，您需要使用scanf()。一元&返回其后面的变量的地址。 scanf()将值存储在该地址中。因此，您需要在&中使用scanf()。但是，您不需要&使用printf()（除非您出于某种原因打印该变量的地址）

您还应该将3 printf()语句更改为

printf("SPEEDING - You have gone over the speed limit.\n Fined $%d.\n",FINE1);
printf("SPEEDING - You have gone over the speed limit.\n Fined $%d .\n", FINE2);
printf("SPEEDING - You have gone over the speed limit.\n Fined $%d .\n", FINE3);

否则，它不会显示FINE的值

无论输入如何，C中的条件仅打印1个结果

1 个答案: