Question

我有以下的旋转表，我设法做了，这是结果，我想进一步。

RID; NTRITCode; NTRIId; Parameter; Usage; Rate**

1; CURRENT; 4; Peak; 100; 0.1
1; CURRENT; 4; NonPeak; 200; 0.2

1; PROPOSED; 6; Peak; 100; 0.2
1; PROPOSED; 6; NonPeak; 200; 0.3

1; PROPOSED; 8; Peak; 200; 0.3
1; PROPOSED; 8; NonPeak; 200; 0.5

如您所见，有2套建议（ID = 6和8）。我想以某种方式显示如下，所以每组都有一对CURRENT以及PROPOSED如下：

**Sequence; RID; NTRITCode; NTRIId; Parameter; Usage; Rate**

1; 1; CURRENT; 4; Peak; 100; 0.1
1; 1; CURRENT; 4; NonPeak; 200; 0.2
1; 1; PROPOSED; 6; Peak; 100; 0.2
1; 1; PROPOSED; 6; NonPeak; 200; 0.3

2; 1; CURRENT; 4; Peak; 100; 0.1
2; 1; CURRENT; 4; NonPeak; 200; 0.2
2; 1; PROPOSED; 8; Peak; 200; 0.3
2; 1; PROPOSED; 8; NonPeak; 200; 0.5

我能想到的只是使用CURSOR和UNION的组合，但有没有可以做到这一点的TSQL？

由于

Answer 1

也许在这个问题上发布的mdma可能对你有用。我从未想过它，但递归CTE非常有趣。起点可以是不同的“建议对”的数量，然后它将根据需要多次与自身结合以创建正确数量的“当前对”

SQL: how to get all the distinct characters in a column, across all rows

Answer 2

我不确定你是否真的需要递归查询和Numbers / Tally表一样，以便为“CURRENT”值获取与“PROPOSED”值相同的序列号。

With 
    Numbers As 
    (
    Select Row_Number() Over ( Order By C1.object_id ) As Value
    From sys.columns As C1
        Cross Join sys.columns As C2
    )
    , ProposedSequences As
    (
    Select  NTRIId
        , Row_Number() Over ( Order By NTRIId ) As Sequence
    From Table
    Where NTRITCode = 'PROPOSED'
    Group By NTRIId
    )
    , CurrentSequences As
    (
    Select RID, NTRITCode, NTRIId, Parameter, Usage, Rate
        , Numbers.Value As Sequence
    From Table
        Cross Join Numbers
    Where NTRITCode = 'Current'
        And Numbers.Value <= (Select Max(Sequence) From ProposedSequence)
    )
Select Sequence, RID, NTRITCode, NTRIId, Parameter, Usage, Rate
From CurrentSequences
Union All
Select PS.Sequence, T.RID, T.NTRITCode, T.NTRIId, T.Parameter, T.Usage, T.Rate
From ProposedSequences As PS
    Join Table As T
        On T.NTRIId = PS.NTRIId
Order By PS.Sequence, T.NTRITCode

Answer 3

select row_number() over(PARTITION by c.NTRITCode,c.parameter order by c.NTRITCode, c.ntriid,c.parameter) nb, 
c.* from table c
join (select * from table where NTRITCode='PROPOSED') p 
on c.rid=p.rid and c.parameter=p.parameter
and not(p.NTRIId=c.NTRIId and c.parameter=p.parameter)
order by nb, c.ntriid, c.parameter desc

其他解决方案而不是Cursoring

3 个答案: