Question

我一直试图解决这个问题一段时间，但还没有找到任何解决方案。 '[String]' does not have a member named 'text' let c:Int? = conversion.text.toInt()。我知道这与字符串是一个浮点有关。会有什么问题？

 @IBOutlet var pickerView1: UIPickerView!

        @IBOutlet var textField1: UITextField!
        @IBOutlet weak var enterUnits: UITextField!
        @IBOutlet var answerConversion: UITextField!
        var measurements = ["m to feet","cm to inches", "mm to inches"]
        var conversion = ["3.12","4.54","5.23"]

pickerview

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)  {
            if pickerView.tag == 0 {

                let a:Int? = enterUnits.text.toInt()
                let c:Int? = conversion.text.toInt()

                let answer = (a!) * (c!)
                textField1.text = measurements[row]
                answerConversion.text = conversion[row]
                answerConversion.text = "\(answer)"

                }

Answer 1

您可以声明Double而不是String

的数组

 let conversion = [3.12,4.54,5.23]

在pickerView中你可以访问

let c = conversion[row]

Answer 2

[String]没有属性文本，这就是您收到错误的原因。您需要先使用索引调用[String]，然后才能将其转换为int。

示例：

myStringArray[myIndex].toInt()

＆＃39; [字符串]＆＃39;没有名为＆＃39; text＆＃39;的成员迅速

2 个答案: