Question

这是我正在尝试的，基本上只为当前用户查询“事件”类的关键“类别”：

class AllEntriesTableViewController: UITableViewController {

var allEntries = [""]

override func viewDidLoad() {
    super.viewDidLoad()

    var user = PFUser.currentUser()

    var query = PFQuery(className:"event")
    query.whereKey("user", equalTo: user)
    query.includeKey("category")

    query.findObjectsInBackgroundWithBlock {
       (objects: [AnyObject]!, error: NSError!) -> Void in
       if error == nil {
         // The find succeeded.
         self.allEntries.removeAll(keepCapacity: true)

        // Do something with the found objects
         for object in objects {
            var allEnt:String = object as String
            self.allEntries.append(allEnt.category)
         }
       } else {
          // Log details of the failure
          NSLog("Error: %@ %@", error, error.userInfo!)
       }
    }

Answer 1

您好像期待allEnt成为String而不是event。

var allEnt:String = object as String
self.allEntries.append(allEnt.category)

如果您打算在allEnt上访问event作为属性，则应该将allEnt.category设为event vars。也许你忘记了某种查找？类似的东西：

convertToEvent(allEnt)
self.keyToEventDictionary[allEnt]

或者，您的objects列表实际上可能是category结果的列表，您应该这样做：

self.allEntries.append(allEnt)

＆＃39; String＆＃34;没有名为＆＃39;类别的成员

1 个答案: