Question

我正在尝试使用以下代码：

fn get_max(string:Vec<BigUint>) -> BigUint {
    let mut max:BigUint = num::zero();

    for i in 0..(string.len()-13) {
        let mut prod:BigUint = num::one();
        for j in i..(i+13) {
            prod.mul(&string[j]);
        }

        if prod.clone().gt(&max) {
            max = prod;
        }
    }

    max
}

但是当我尝试编译时出现以下错误：

src/main.rs:13:4: 13:8 error: use of moved value: `prod`
src/main.rs:13          prod.mul(&string[j]);
                        ^~~~
note: `prod` was previously moved here because it has type `num::bigint::BigUint`, which is non-copyable
src/main.rs:16:6: 16:10 error: use of moved value: `prod`
src/main.rs:16      if prod.clone().gt(&max) {
                       ^~~~
src/main.rs:13:4: 13:8 note: `prod` moved here because it has type `num::bigint::BigUint`, which is non-copyable
src/main.rs:13          prod.mul(&string[j]);
                        ^~~~
src/main.rs:17:10: 17:14 error: use of moved value: `prod`
src/main.rs:17          max = prod;
                              ^~~~
src/main.rs:13:4: 13:8 note: `prod` moved here because it has type `num::bigint::BigUint`, which is non-copyable
src/main.rs:13          prod.mul(&string[j]);
                        ^~~~
error: aborting due to 3 previous errors

据我所知，我永远不会移动prod，所以出了什么问题？

Answer 1

prod.mul是来自Mul特征的乘法方法，它采用两个值（两个操作数）并返回另一个（结果）。在这种情况下，它按值prod，因此prod被消耗，移入方法调用。

您的意思是prod = prod.mul(&string[j]);，可以使用*运算符更好地编写，而不是调用mul方法：prod = prod * &string[j];（对不起，prod *= &string[j]没有'工作了。）

在乘以数字时移动值

1 个答案: