Question

当i = 1执行时，我的应用程序在语句(sqlite3_step(insertAlert) == SQLITE_DONE)上崩溃。任何人都可以告诉我它崩溃的原因吗？

sqlite3_stmt *insertAlert;

textmeAppDelegate *textme = (textmeAppDelegate *)[[UIApplication sharedApplication] delegate];

NSString *insert = @"INSERT INTO alerts (alert_id, email_address, messege_text, when_to_send, how_often_send, recipient_phone_number) VALUES(?, ?, ?, ?, ?, ?)";
if(sqlite3_prepare_v2(textme.dbConn, [insert UTF8String], -1, &insertAlert, NULL) == SQLITE_OK)
{
    NSDictionary *tmpDictionary;
    NSString *alertId;
    for(int i=0; i<[keys count]; i++)
    {
        alertId = [NSString stringWithFormat:@"%@", [keys objectAtIndex:i]];
        tmpDictionary  = [NSDictionary dictionaryWithDictionary:[dictionary2 objectForKey:alertId]];

        sqlite3_bind_text(insertAlert, 1, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"alert_id"]], -1, SQLITE_TRANSIENT);
        sqlite3_bind_text(insertAlert, 2, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"email_address"]], -1, SQLITE_TRANSIENT);
        sqlite3_bind_text(insertAlert, 3, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"messege_text"]], -1, SQLITE_TRANSIENT);
        sqlite3_bind_text(insertAlert, 4, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"when_to_send"]], -1, SQLITE_TRANSIENT);
        sqlite3_bind_text(insertAlert, 5, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"how_often_send"]], -1, SQLITE_TRANSIENT);
        sqlite3_bind_text(insertAlert, 6, [NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"recipient_phone_number"]], -1, SQLITE_TRANSIENT);

        if (sqlite3_step(insertAlert) == SQLITE_DONE) {
            sqlite3_reset(insertAlert);
            sqlite3_clear_bindings(insertAlert);
        }
        else {
            NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(textme.dbConn));
            //[textme showError:@"Device Error" errMsg:sqlite3_errmsg(textme.dbConn)];
            return FALSE;
        }

    }
    sqlite3_finalize(insertAlert);
}

Answer 1

你认为sqlite3_bind_text（）能理解如何处理NSString吗？我没有。

我很惊讶

即使在i == 0
你没有看到所有这些绑定的编译器警告。

要解决此问题，您需要更换

[NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"alert_id"]]

与

[[NSString stringWithFormat:@"%@", [tmpDictionary objectForKey:@"alert_id"]] UTF8String]

和所有其他sqlite3_bind_text（）行类似。

sqlite3崩溃第二个插入语句

1 个答案: