Question

我得到的错误是＆＃34; INSERT语句与FOREIGN KEY约束冲突＆＃34; FK_vacation_users＆＃34;。冲突发生在数据库＆＃34; TestAtt＆＃34;，table＆＃34; dbo.users＆＃34;，column＆＃39; userID＆＃39;。＆＃34;

我试图通过以下方式插入用户：

INSERT into users (firstName, lastName, userName, password, team, fingerID, type, isActive) VALUES ('{0}', '{1}', '{2}', '{3}', '{4}', '{5}', '{6}', '{7}')",
firstNameAddBox.Text, lastNameAddBox.Text, userNameAddBox.Text, passwordAddBox.Text,
teamAddUserCombo.Text, fingerIdAddBox.Text, userTypeAddCombo.SelectedValue, isActiveCheck.Checked);

我的用户表如下所示：

CREATE TABLE
    users
    (
        userID INT NOT NULL IDENTITY,
        userName NVARCHAR(50) COLLATE Romanian_CI_AS NOT NULL,
        password NVARCHAR(100) COLLATE Romanian_CI_AS NOT NULL,
        firstName NVARCHAR(50) COLLATE Romanian_CI_AS NOT NULL,
        lastName NVARCHAR(50) COLLATE Romanian_CI_AS NOT NULL,
        team TINYINT NOT NULL,
        type TINYINT NOT NULL,
        fingerID SMALLINT NOT NULL,
        isActive BIT DEFAULT 1 NOT NULL,
        CONSTRAINT PK_users PRIMARY KEY (userID),
        CONSTRAINT FK_users_userType FOREIGN KEY (type) REFERENCES userType (typeID),
        CONSTRAINT users_idx UNIQUE (fingerID)
    );

假期表如下所示：

CREATE TABLE
    vacation
    (
        ID INT NOT NULL IDENTITY,
        userID INT NOT NULL,
        vacation TINYINT DEFAULT 0 NOT NULL,
        extraDays TINYINT DEFAULT 0 NOT NULL,
        PRIMARY KEY (ID),
        CONSTRAINT FK_vacation_users FOREIGN KEY (ID) REFERENCES users (userID)
    );

这就是触发器：

ALTER TRIGGER "dbo"."newUserTrigger"
  on "dbo"."users"
  AFTER INSERT
  as 
begin
DECLARE @newUserID int
SELECT @newUserID = (SELECT userID FROM Inserted)
INSERT INTO vacation (userID) VALUES (@newUserID)
end;

因此，如果我禁用触发器，插件可以正常工作，但触发器似乎也不会在度假表中插入userID。

Answer 1

我认为您的外键不正确，引用users的列是userID，而不是ID：

 CONSTRAINT FK_vacation_users FOREIGN KEY (userID) REFERENCES users (userID)

但您的触发器也已损坏，因为inserted可以包含多个（或无）行。所以它应该是：

ALTER TRIGGER "dbo"."newUserTrigger"
  on "dbo"."users"
  AFTER INSERT
  as 
begin
INSERT INTO vacation (userID) SELECT userID from Inserted
end;

Answer 2

问题在于：

CONSTRAINT FK_vacation_users FOREIGN KEY (ID) REFERENCES users (userID)

这就是假期中的ID列必须在用户的userId中具有匹配值。我认为（ID）应该是（userID）。它应该工作正常。

Answer 3

CONSTRAINT FK_vacation_users FOREIGN KEY (ID) REFERENCES users (userID)

应该是

CONSTRAINT FK_vacation_users FOREIGN KEY (userID) REFERENCES users (ID)

由于触发器，插入语句崩溃

3 个答案: