我正在尝试关注this example,但它无效。 offset
会导致问题吗?
这就是我所拥有的:
Sub parse_dates_flurry()
Dim col_diff As Integer ' how many columns away the unparsed date
col_diff = -20
Dim num_of_char As Integer
num_of_char = 10
Dim sheet_name_flurry As String
sheet_name_flurry = "flurry_an_output.csv"
' get rows used in sheet
Dim rows1 As Long
rows1 = Get_Rows_Generic(sheet_name_flurry, 1)
' find last column and fill with formula
Dim formula_parse As String
formula_parse = "=LEFT(RC[col_dif],num_of_char)" '
Dim starting_cell_range As Range
Dim n As Long
With Worksheets(sheet_name_flurry)
Set starting_cell_range = .Range(find_last_column(sheet_name_flurry))
starting_cell_range.Offset(0, 1) = "Parsed date"
For n = 1 To (rows1 - 1)
' getting error here:
starting_cell_range.Offset(n, 1).Formula = formula_parse
Next n
End With
End Sub
答案 0 :(得分:2)
formula_parse = "=LEFT(RC[col_dif],num_of_char)"
应该是这样的:
formula_parse = "=LEFT(RC[" & col_dif & "]," & num_of_char & ")"
请记住,formula_parse
是一种正确的字符串形式
但要将变量的值连接到它,你需要像上面那样进行
由于您要以R1C1
表示法传递公式,请更改此行:
starting_cell_range.Offset(n, 1).Formula = formula_parse
到此:
starting_cell_range.Offset(n, 1).FormulaR1C1 = formula_parse