Question

您好我是C ++的新手，并且我试图理解为什么在使用循环更新数组中的结构时，它会跳过数组下一次迭代的getline以获得更多的扬声器。

#include <iostream>
#include <string>
using namespace std;

struct speaker
{
    string speakerName;
    string telephone;
    string topic;
    int fee;
};


int main() {
    speaker speakerList[3]; // define array named speakerList with 10 elements of the structure speaker

    for (int index = 0; index < 3; index++)
    {
        //cout << "Index number: " << index << endl;
        cout << "Input speaker name: ";
        //cin >> speakerList[index].speakerName;
        getline (cin,speakerList[index].speakerName);

        //cout << "Index number: " << index << endl;
        cout << "Input telephone number: ";
        cin >> speakerList[index].telephone;

        //cout << "Index number: " << index << endl;
        cout << "Input speech topic: ";
        cin >> speakerList[index].topic;

        //cout << "Index number: " << index << endl;
        cout << "Input fee: ";
        cin >> speakerList[index].fee;
        cout << "" << endl;
    }

    // Array output of struct speaker for elements 0 - 3
    // Display all speakers and their data
    for (int index = 0; index < 3; index++)
    {
        cout << "Speaker Name: " << speakerList[index].speakerName << endl;
        cout << "Speaker Phone Number: " << speakerList[index].telephone << endl;
        cout << "Speaker Topic: " << speakerList[index].topic << endl;
        cout << "Speaker Fee: " << speakerList[index].fee << endl;
        cout << "" << endl;
    }

    // change attribute of speaker
    // get speaker list so user can select speaker to modify
    cout << "Speaker number and name below. " << endl;
    for (int index = 0; index < 3; index++)
    {
        cout << index << ". " << speakerList[index].speakerName << endl;
    }

    int speakerNum; // declare speaker number variable
    cout << "Input number of speaker to update: ";
    cin >> speakerNum;

    cout << "Update speaker " << speakerNum << " data." << endl;
    cout << "" << endl;
    cout << "Update speaker name: ";
    //cin >> speakerList[speakerNum].speakerName;
    getline(cin, speakerList[speakerNum].speakerName);

    cout << "Update telephone number: ";
    cin >> speakerList[speakerNum].telephone;

    cout << "Update speech topic: ";
    cin >> speakerList[speakerNum].topic;

    cout << "Update fee: ";
    cin >> speakerList[speakerNum].fee;

    // Display updated speaker results
    for (int index = 0; index < 3; index++)
    {
        cout << "Speaker Name: " << speakerList[index].speakerName << endl;
        cout << "Speaker Phone Number: " << speakerList[index].telephone << endl;
        cout << "Speaker Topic: " << speakerList[index].topic << endl;
        cout << "Speaker Fee: " << speakerList[index].fee << endl;
        cout << "" << endl;
    }

    system("pause");
    return 0;
}

在测试getline的用户输入时，第一个循环没有问题。但是当输入下一个扬声器数据时，它会跳过其余循环的speakerName部分。

我在帖子中找到了一些信息：Why getline skips first line? 我不完全理解它，当我输入帖子中提到的命令时：std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); 它允许用户输入数据，但无法正确地将其添加到数组中。

任何帮助你都非常感激

谢谢

在循环中更新struct时，getline跳过行

0 个答案: