Question

当我运行此程序并选择选项1时，它会同时在cout中打印void CTree::Add()个语句，跳过cin.getline(newPerson->name, 20);

我在链接列表程序中有相同的代码片段并且表现正常，我真的很想解决这个问题。

    //header file

using namespace std;

struct PersonRec
{
    char name[20];
    int bribe;
    PersonRec* leftLink;
    PersonRec* rightLink;
};


class CTree
{

private:
    PersonRec *tree;
    bool IsEmpty();
    void AddItem( PersonRec*&, PersonRec*);
    void DisplayTree(PersonRec*);

public:
    CTree();
    //~CTree();
    void Add();
    void View();

};

//implementation file`

#include <iostream>
#include <string>

using namespace std;

#include "ctree.h"

CTree::CTree()
{
    tree = NULL;
}

//PersonList::~MyTree()
//{
//
//}


bool CTree::IsEmpty()
{
    if(tree == NULL) 
    {
        return true;
    }
    else
    {
        return false;
    }
}

void CTree::Add()
{
    PersonRec* newPerson = new PersonRec();

    cout << "Enter the person's name: ";
    cin.getline(newPerson->name, 20);
    cout << "Enter the person's contribution: ";
    cin >> newPerson->bribe;


    newPerson->leftLink = NULL;
    newPerson->rightLink = NULL;

    AddItem(tree, newPerson);
}

void CTree::View()
{
    if (IsEmpty())
    {
        cout<<"The list is empy";
    }
    else
    {
        DisplayTree(tree);

    }

};

void CTree::AddItem( PersonRec*& ptr, PersonRec* newPer )
{
        if (tree == NULL)
        {
            ptr = newPer;
        }
        else if ( newPer->bribe < ptr->bribe)
            AddItem(ptr->leftLink, newPer); 
        else
            AddItem(ptr->rightLink, newPer); 
}
void CTree::DisplayTree(PersonRec* ptr)
{
    if (ptr == NULL)
                    return;
    DisplayTree(ptr->rightLink);
    cout<<ptr->name<<" "<<"$"<<ptr->bribe <<endl;
    DisplayTree(ptr->leftLink); 
}

    //driver file
    #include <iostream>

using namespace std;
#include <cstdlib>
#include "ctree.h"

int displayMenu (void);
void processChoice(int, CTree&);

int main (void)
{
int num;
CTree ct;
do 
{
num = displayMenu();
if (num != 3)
processChoice(num, ct);
} while (num != 3);
return 0;
}

int displayMenu (void)
{
int choice;
cout << "\nMenu\n";
cout << "==============================\n\n";
cout << "1. Add student to waiting list\n";
cout << "2. View waiting list\n";
cout << "3. Exit program\n\n";
cout << "Please enter choice: ";
cin >> choice;
return choice;
}

void processChoice(int choice, CTree& myTree)
{
   switch (choice)
   {
      case 1: myTree.Add (); break;
      case 2: myTree.View (); break;
   } 
}

Answer 1

在choice子例程中阅读displayMenu后，您将保留用户输入行的其余部分。具体而言，您将保留行末指示符：'\n'。稍后，当您阅读newperson->name时，您实际上正在检索菜单行的其余部分，而不是名称行。

在尝试阅读名称之前，您可以使用istream::ignore来使用剩余的菜单选项行。

将displayMenu的最后两行替换为：

cin >> choice;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
return choice;

Answer 2

添加

cin.ignore(2000, '\n');

在输入调用修复问题之前

！

程序跳过getline

2 个答案: