将RoR视图转换为Java

时间:2010-05-25 18:06:41

标签: java ruby-on-rails groovy

由于某些原因,我试图将以下RoR视图代码转换为GSP视图:

List<Object> objects包含我要在3列中显示的数据

<% 
modulo_objects = @objects.length % 3
base = @objects.length / 3
base = base.ceil
case modulo_objects
  when 0
 cols = [base, base, base]
  when 1
 cols = [base, base + 1, base]
  when 2
 cols = [base + 1, base, base + 1]
end

counter = 0
%>

<% 3.times do |i| %>
 <td width="220" align="center" style="padding-right: 15px;">
      <% cols[i].times do %>
  <h1><a href="/objects/show/<%= @objects[counter].urlname %>" ><%= @objects[counter].name %></a></h1>
  <% counter = counter + 1 %>
  <% end %>
 </td>
<% end %>

这是我到目前为止所得到的:

#{extends 'main.html' /}
%{
modulo_objects = objects.size() % 3
base = objects.size() / 3
base = Math.ceil(base)
if(modulo_objects == 0)
    cols = [base, base, base]
else if(modulo_objects == 1)
    cols = [base, base + 1, base]
else if(modulo_objects == 2)
    cols = [base + 1, base, base + 1]
endif

counter = 0

}%

 #{list items:1..3, as:'i'}
     <td width="220" align="center" style="padding-right: 15px;">
         #{list items:cols[i]}
            <a href="@{Objects.show(objects.get(counter).name.replaceAll(" ", "-"))}" >${objects.get(counter).name}</a>
            %{ counter = counter + 1 }%
         #{/list}
     </td>
 #{/list}

这个想法是将项目组织成3列,例如1 | 0 | 1 4 | 5 | 4或5 | 4 | 5, 我真的不明白#{list items:cols[i]}是否会重现ruby的cols[i].times do

到目前为止,Java视图不会显示两个以上的元素。

2 个答案:

答案 0 :(得分:0)

只是评论(抱歉没有特权):

我认为你的html上面的代码应该转到你的控制器,因为编码风格会使你的MVC框架无效:P只是说

答案 1 :(得分:0)

  public static List<Object>[] splitIn(List<Object> objects, int i) {

    int base_objects = objects.size() / i;
    int modulo_objects = objects.size() % i;
    int[] colSize = new int[i];

    switch (modulo_objects) {
        case 0:
            colSize[0] = base_objects;
            colSize[1] = base_objects;
            colSize[2] = base_objects;
            break;
        case 1:
            colSize[0] = base_objects;
            colSize[1] = base_objects + 1;
            colSize[2] = base_objects;
            break;
        case 2:
            colSize[0] = base_objects + 1;
            colSize[1] = base_objects;
            colSize[2] = base_objects + 1;
            break;
    }

    List<Object>[] columns = new List[i];

    int count = 0;
    for (int x = 0; x < i; x++) {
        List<Object> col_objects = new ArrayList();
        int colCount = 0;
        while (colCount < colSize[x]) {
            Object Object = (Object) objects.get(count);
            col_objects.add(Object);
            colCount++;
            count++;
        }
        columns[x] = col_objects;
    }
    return columns;
}






#{list cols, as:'column'}
  <td width="220" align="center" style="padding-right: 15px;">
      #{list column, as:'object'}
                <h1><a href="@{Objects.show(object.urlName())}" >${object.name}</a></h1>
      #{/list}
   </td>
   #{/list}