我有几个这样的陈述:
if (mediaCode.IndexOf(',') > 0) {
entries = entries.Where(c => mediaCode.Contains(c.Mediacode));
}
else {
entries = entries.Where(c => c.Mediacode == mediaCode);
}
然后:
if (contentType.IndexOf(',') > 0) {
entries = entries.Where(c => contentType.Contains(c.Contenttype));
}
else {
entries = entries.Where(c => c.Contenttype == contentType);
}
我想创建一个函数,我只是传递字符串和属性, 类似于:MethodName(contentType,c.Contenttype)
怎么可以这样做?
答案 0 :(得分:0)
使用反射(参见How to get a property value based on the name),您可以这样做:
protected void FilterStrings(ref IEnumerable<StringStruct> entries, string contentType, string fieldName)
{
if (contentType.IndexOf(',') > 0)
{
entries = entries.Where(c => contentType.Contains(c.GetType().GetProperty(fieldName).GetValue(c, null).ToString()));
}
else
{
entries = entries.Where(c => c.GetType().GetProperty(fieldName).GetValue(c, null).ToString() == contentType);
}
}
您可以像这样调用函数:
FilterStrings(ref entries, mediaCode, "Mediacode");