Question

无法将表单节点转换为对象

我无法在以下XML中解组表单节点：

<?xml version="1.0" encoding="UTF-8"?>
    <start>
        <action>
            <application>
                <name>sarat</name>
            </application>
            <forms>
                <form>
                    <name>flexMobile</name>
                    <type>flex</type>
                    <channel>mobile</channel>
                </form>
                <form>
                    <name>flexMobile1</name>
                    <type>flex1</type>
                    <channel>mobile1</channel>
                </form>
            </forms>
        </action>
    </start>

感谢表单上是否有任何指针并将表单节点转换为对象

Start.js

package com.jaxb;

import javax.xml.bind.annotation.XmlElement;  
import javax.xml.bind.annotation.XmlRootElement; 

@XmlRootElement
public class Start {
    Action action;

    @XmlElement
    public Action getAction(){
        return action;
    }
    public void setAction(Action action){
        this.action = action;
    }
}

Action.js

package com.jaxb;

import javax.xml.bind.annotation.*;
import java.util.List;

public class Action {
    private Application application;
    private List<Form> forms;

    public Action(){}
    public Action(Application application, List<Form> forms){
        super();
        this.application = application;
        this.forms = forms;
    }

    @XmlElement
    public Application getApplication(){
        return this.application;
    }
    public void setApplication(Application application){
        this.application = application;
    }

    @XmlElement
    public List<Form> getForms(){
        return forms;
    }
    public void setForms(List<Form> forms){
        this.forms = forms;
    }
}

Application.js

package com.jaxb;

import javax.xml.bind.annotation.XmlElement;

public class Application {
    private String name;

    @XmlElement
    public String getName(){
        return name;
    }
    public void setName(String name){
        this.name = name;
    }
}

Forms.js

package com.jaxb;

import java.util.List; 
import javax.xml.bind.annotation.XmlElement;

public class Forms {
    private List<Form> form;

    @XmlElement
    public List<Form> getForm(){
        return form;
    }
    public void setForms(List<Form> form){
        this.form = form;
    }
}

Form.js

package com.jaxb;

import javax.xml.bind.annotation.*;

public class Form {
    private String name;
    private String type;
    private String channel;

    private Form(){}
    private Form(String name, String type, String channel){
        super();
        this.name = name;
        this.type = type;
        this.channel = channel;
    }

    @XmlElement
    public String getName(){
        return name;
    }
    public void setName(String name){
        this.name = name;
    }

    @XmlElement
    public String getType(){
        return type;
    }
    public void setType(String type){
        this.type = type;
    }

    @XmlElement
    public String getChannel(){
        return channel;
    }
    public void setChannel(String channel){
        this.channel = channel;
    }
}

我无法构造Forms类以将xml转换为对象，感谢是否有任何建议

Parser.js

package com.jaxb;

import java.io.File;  
import java.util.List;  
import javax.xml.bind.*;  

public class Parse {
    public static void main(String[] args) {  

        try {  

            File file = new File("data.xml");  
            JAXBContext jaxbContext = JAXBContext.newInstance(Start.class);  

            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();  
            Start que= (Start) jaxbUnmarshaller.unmarshal(file);  


            Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            marshaller.marshal(que, System.out);    
        } catch (JAXBException e) {  
            e.printStackTrace();  
        }  

    }  
}

Answer 1

xml和类之间存在不匹配。 xml建议您使用包含Form元素列表的Object Forms。你的java模型，直接在Action下有Form元素。所以unmarshaller希望xml像这样：

<action>
            <application>
                <name>sarat</name>
            </application>

                <forms>
                    <name>flexMobile</name>
                    <type>flex</type>
                    <channel>mobile</channel>
                </forms>
                <forms>
                    <name>flexMobile1</name>
                    <type>flex1</type>
                    <channel>mobile1</channel>
                </forms>

        </action>

如果从xml开始，请生成xsd架构（可以为您执行此操作的网页）并使用它来生成jaxb类。这样你就可以避免这种错误

Answer 2

在forms.js中，在添加名称值后，代码工作了

package com.jaxb;
import java.util.List; 
import javax.xml.bind.annotation.XmlElement;
public class Forms {
    private List<Form> form;
    @XmlElement(name="forms)
    public List<Form> getForm(){
        return form;
    }
    public void setForms(List<Form> form){
        this.form = form;
    }
}

下面的xml的JAXB类声明

2 个答案: