我有以下SQL服务器查询:
SELECT G.StyleID,
G.Size, Count(*) As 'Count',
G.PropertyID FROM TBL_Garment G
LEFT OUTER JOIN TBL_EmployeeJob ON TBL_EmployeeJob.ID = G.EmployeeJobID
LEFT OUTER JOIN TBL_DepartmentJob ON TBL_DepartmentJob.ID = TBL_EmployeeJob.DepartmentJobID
LEFT OUTER JOIN TBL_Department ON TBL_Department.ID = TBL_DepartmentJob.DepartmentID
LEFT OUTER JOIN TBL_Division ON TBL_Division.ID = TBL_Department.DivisionID
LEFT OUTER JOIN TBL_Job ON TBL_Job.ID = TBL_DepartmentJob.JobID
WHERE G.EmployeejobiD IS NOT NULL
AND TBL_Division.ID = N'1'
AND TBL_Department.ID = N'1'
AND TBL_Job.ID = N'1'
AND G.PropertyID = 1
GROUP BY G.StyleID, G.Size, G.PropertyID
ORDER BY G.StyleID
以下是此查询返回的结果:
现在我需要在此表中添加2个列:
一个是StyleID(总计)的计数总和,另一个是计数/总计。
我确信我可以自己获取计数/总数,但不知道如何获得总计列,或者即使可能。>
以下是我希望表格的版本:
答案 0 :(得分:0)
您可以使用窗口函数:
sum([Count]) over (partition by [StyleID])
尽管如此,请确保它对你的表现非常好。