Question

我有以下查询

select COUNT(mc_owner) as nbr , mc_owner
from [dbo].[full] 
where (date_reception > '01-01-2015')
group by (mc_owner)
order by nbr desc

这告诉我

20000 element1

10000 element2

10000 element3

10000 element4

我需要只有两个结果element1和其他组合在元素上

之类的东西

element1 20000

其他30000

感谢您的帮助

Answer 1

使用CASE表达式执行此操作，如下所示：

SELECT
    COUNT(*) as nbr,
    CASE mc_owner WHEN 'Element1' THEN 'Element1' ELSE `Others` END as Owner
FROM [dbo].[full] 
WHERE (date_reception > '01-01-2015')
GROUP BY CASE mc_owner WHEN 'Element1' THEN 'Element1' ELSE `Others` END
ORDER BY COUNT(*) DESC

我们的想法是提供一个表达式，根据'Element1'字段的值，评估您需要的两个值之一 - 即Others或mc_owner。

Answer 2

declare   @tt table(name varchar(10),id int)

insert into @tt(name,id)values ('element1',2000)
insert into @tt(name,id)values ('element2',2000)
insert into @tt(name,id)values ('element3',2000)
insert into @tt(name,id)values ('element4',2000)


;WITH CTE AS
(
select ROW_NUMBER()OVER(Partition by ID ORDER BY ID,name) RN, * from @tt 

)
select NAME,ID from CTE
where RN = 1
UNION ALL
select 'Others' as NAME,SUM(id) as ID 
from CTE
where RN >1

Sql Server group by，count查询

2 个答案: