使用带有networkx的链接矩阵绘制有向图

Question

我正在为一个学校项目的pagerank工作，我有一个矩阵，其中行“i”代表从站点j（行）到站点i的链接。 （如果还不清楚我会解释更多）。

目前的部分是：

Z=[[0,1,1,1,1,0,1,0,0,0,0,0,0,0],[1,0,0,0,1,0,0,0,0,0,0,0,0,0],    [1,1,0,0,0,0,0,0,0,0,0,0,0,0],[1,0,1,0,0,0,0,0,0,0,0,0,0,0],[1,0,0,1,0,0,0,0,0,0,0,0,0,0],[1,0,0,0,0,0,0,1,0,1,0,0,0,0],[0,0,0,0,0,1,0,0,0,0,0,0,0,0],[0,0,0,0,0,1,1,0,1,0,0,0,0,0],[0,0,0,0,0,1,0,0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,1,0,1,1,1,1],[0,0,0,0,0,0,0,0,0,1,0,0,0,1],[0,0,0,0,0,0,0,0,0,1,1,0,0,0],[0,0,0,0,0,0,0,0,0,1,0,1,0,0],[0,0,0,0,0,0,0,0,0,1,0,0,1,0]]
A=np.matrix(Z)
G=nx.from_numpy_matrix(A,create_using=nx.MultiDiGraph())
pos=nx.circular_layout(G)
labels={}
for i in range (N):
    labels[i]=i+1
nx.draw_circular(G)
nx.draw_networkx_labels(G,pos,labels,font_size=15)

我遇到的问题是标签不在它们应该的位置，似乎networkx只是顺时针放置它们......

另外，我怎么能轻松指导图表，这样从j到i的链接不会从i到j？

谢谢！

Answer 1

import numpy as np
import matplotlib.pyplot as plt
import networkx as nx

Z = [[0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 1, 1],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0]]

G = nx.from_numpy_matrix(np.array(Z), create_using=nx.MultiDiGraph())
pos = nx.circular_layout(G)
nx.draw_circular(G)
labels = {i : i + 1 for i in G.nodes()}
nx.draw_networkx_labels(G, pos, labels, font_size=15)
plt.show()

产量

这个结果对我来说是正确的。请注意，例如，标记为1的节点的有向边指向2，3，4，5和7。这对应于数组中第一行的Z[0]：

[0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0]

因为第一行对应于节点1，而该行中的那些对应于节点2，3，4，5和{ {1}}。