Question

我的数据库中有以下表格

----------------------
id | keyword    | location 
----------------------
1  | Test-New   |    1
2  | Test       |    1
3  | Test       |    1
4  | Test       |    1
----------------------

我需要根据位置获得结果，所以我使用分组

select keyword, location ,count(*) as count from table_name group by location

现在我得到以下结果

----------------------------
keyword    | Location |  count
---------------------------
Test-New   |    1     |   4
---------------------------

但我希望每个位置的最热门关键字和每个位置的数量。在这个例子中，我需要测试而不是测试新用于位置 1 （因为在实际的表中，测试出现了3次并且Test-New出现了1次）。

所以我需要这样的结果

--------------------------
keyword | Location |  count
--------------------------
Test    |    1     |   4
--------------------------

Answer 1

您可以尝试此查询：

select keyword ,count(keyword) as TotalKeyword from table_name group by location

Answer 2

SELECT a.*
  FROM 
     ( SELECT keyword
           , location
           , COUNT(*) cnt 
        FROM my_table 
       GROUP 
          BY keyword
           , location
     ) a
  JOIN
     ( SELECT keyword
            , MAX(cnt) max_cnt
         FROM 
            ( SELECT keyword
                   , location
                   , COUNT(*) cnt 
                FROM my_table 
               GROUP 
                  BY keyword
                   , location
            ) x 
        GROUP 
           BY keyword
     ) b
    ON b.keyword = a.keyword
   AND b.max_cnt = a.cnt;

Answer 3

这是正常工作......享受RaGu bhai

   SELECT  
temp.keyword,temp.location,SUM(temp.TotalLocation) AS COUNT
 FROM (SELECT 
    keyword,location,
    COUNT(location) AS TotalLocation
  FROM
    `test` 
  GROUP BY location,keyword ORDER BY TotalLocation DESC)
  temp GROUP BY location;

demo execute here

Answer 4

你的问题有点混乱，你要问这样的事吗？

select *,
count(location) as location_count
from test1 group by location, keyword

在mysql中分组时获取最大可能值

4 个答案: