Question

有谁能告诉我们如何将图像分成8X8块？

我可以读取图像，但不能将其划分为DCT的8x8子矩阵。

int main()
{
    FILE *image_raw;
    unsigned char **matriz_image;
    int i, j;
    int rows=1080, colums=1920;

    matriz_image = (unsigned char  **) malloc (rows*sizeof(unsigned char *));

    //i create dinamic colums
    for(i=0; i<rows; i++)
    {
        matriz_image[i] = (unsigned char *) malloc (colums*sizeof(unsigned char ));
    }

    //i open image raw
    image_raw =  fopen("imag.dat", "r+b");
    //i copy values to matriz_image


    for (i = 0; i < rows; ++i)
    {
        fread(matriz_image[i], sizeof(unsigned char ), colums, image_raw);
    }


    for(i=0; i<rows; i++)
    {
        for(j=0; j<colums; j++)
        {
            // printf("%i ",*(*(matriz_image+i)+j));
            printf("%i ",matriz_image[i][j]);
        }
        printf("\n");
    }

Answer 1

你可以这样做：

void dct(unsigned char **m, int baserow, int basecol)
{
  for (int row = baserow, endrow = baserow + 8; row < endrow; ++row)
    for (int col = basecol, endcol = basecol + 8; col < endcol; ++col)
      ; // operate on m[row][col]
}

int do_dcts(unsigned char **m, int num_rows, int num_cols)
{
  if (num_rows <= 0 || num_rows % 8 || num_cols <= 0 || num_cols % 8)
    return -1;

  for (int row = 0; row < num_rows; row += 8)
    for (int col = 0; col < num_cols; col += 8)
      dct(m, row, col);    

  return 0;
}

通过使用两个指针级别实现2D数组，您正在浪费空间并恶化您的内存局部性。最好做一次分配然后适当地偏移到数组中：

int main()
{
    FILE *image_raw;
    unsigned char *matriz_image;
    int i, j;
    int rows=1080, colums=1920;

    matriz_image = malloc(rows*colums*sizeof(unsigned char));

    ...

如果您可以创建行和列常量或具有VLA，那么您可以执行以下操作：

unsigned char (*m)[colums] = (unsigned char (*)[colums]) matriz_image;

m[5][2] = 2; // double indexed access without extra pointers + allocs

同样，您可以将m指针的矩阵传递给您的函数以对其进行操作。

如果你不能使行和列成为编译时常量并且你没有VLA，那么你可以编写辅助fcns来为你做指针运算：

inline unsigned char *get_row(unsigned char *m, int numcols, int row)
{
  return &m[row * num_cols];
}

inline unsigned char *get_elem(unsigned char *m, int numcols, int row, int col)
{
  return &m[row * num_cols + col];
}

...

*get_elem(m, colums, 5, 2) = 2;  // double indexing not as nice but good memory usage

如果您确实需要快速完成这些操作，那么当您读取图像时，可以重新组织它以在内存中连续放置8x8字节块以获得最佳缓存性能：

// organize m like m[rows * colums / 64][8][8]; so first index is an 8x8 block #

for (int k = 0; k < rows / 8; ++k)        // read all rows in chunks of 8
  for (int i = 0; i < 8; ++i)             // read 8 rows
    for (int j = 0; j < colums / 8; ++j)  // read 1 row in 8 byte chunks
      fread(&m[k * 8 * colums + i * 8 + j * 64], 1, 8, image_raw);

...

typedef unsigned char (*block_ptr)[8];

inline block_ptr get_block(unsigned char *m, int num_cols, int block_num)
{
  return (block_ptr) &m[block_num * 64];
}

inline block_ptr get_block2(unsigned char *m, int num_cols, int row, int col)
{
  if (row % 8 || col % 8)
    return NULL;

  return (block_ptr) &m[row * num_cols + col * 8];
}

...

for (int k = 0; k < rows * colums / 64; ++k)
{
  block_ptr block = get_block(m, num_colums, k);

  for (int i = 0; i < 8; ++i)
    for (int j = 0; j < 8; ++j)
      ;  // operate on block[i][j];
}

图像在C中划分为DCT

1 个答案: