将LinkedHashset内容复制到新的ArrayList?

时间:2015-03-09 05:55:27

标签: java android arraylist linkedhashset

我的listView最初有一些内容。如果获得的内容相同,我会通过linkedhashset删除重复内容。现在,我想将linkedhashset内容复制到新的ArrayList,即没有重复内容。

我试图复制

p.addAll(0,lhm);  // P is the instance of  ArrayList and lhm is linkedHashset instance

但是,ArrayList也包含重复内容。

示例:

 ArrayList<Price> p = new ArrayList<Price>();

     p.add(new Price("Banana", 60));
     p.add(new Price("Apple", 80));

    LinkedHashSet<Price> lhm = new LinkedHashSet<Price>(p); 
    lhm.add(new Price("Banana", 20)); 
    lhm.add(new Price("Apple", 40));
    lhm.add(new Price("Orange", 30)); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    } 
    Price duplicate = new Price("Banana", 20);
    System.out.println("inserting duplicate object..."); 
    lhm.add(duplicate);
    lhm.add(new Price("Apple", 40));
    p.addAll(0,lhm);
    System.out.println("After insertion:"); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    }

    for (int i = 0; i < p.size(); i++) {

        System.out.println(p.get(i).getItem() +"-" +p.get(i).getPrice());           
    }

Price.class

class Price
{
    private String item; 
    private int price; 
    public Price(String itm, int pr)
    {
        this.item = itm; 
        this.price = pr; 
        }
    public int hashCode()
    { 
        System.out.println("In hashcode");
        int hashcode = 0; 
        hashcode = price;
        //System.out.println(hashcode);

        hashcode+= item.hashCode(); 
    //  System.out.println(hashcode);

        return hashcode;  
        }

    public boolean equals(Object obj)
    {
        System.out.println("In equals"); 
        if (obj instanceof Price) 
        {
            Price pp = (Price) obj; 
            return (pp.item.equals(this.item) && pp.price == this.price); 
            }
        else 
        { 
            return false;
            }
        }

    public String getItem()
    {
        return item; 
    }

    public void setItem(String item) 
    { 
        this.item = item; 
        }

    public int getPrice() 

    {
        return price;
        }
    public void setPrice(int price) 
    {
        this.price = price; 
        }
    public String toString()
    {
        return "item: "+item+" price: "+price; 
        }
    }

输出:

In hashcode
In hashcode
In hashcode
In hashcode
In hashcode
item: Banana price: 60
item: Apple price: 80
item: Banana price: 20
item: Apple price: 40
item: Orange price: 30
inserting duplicate object...
In hashcode
In equals
In hashcode
In equals
//iterating linkedhasset content

After insertion:
item: Banana price: 60
item: Apple price: 80
item: Banana price: 20
item: Apple price: 40
item: Orange price: 30

// iterating ArrayList p content

Banana-60
Apple-80
Banana-20
Apple-40
Orange-30
Banana-60
Apple-80 <-- duplicate

3 个答案:

答案 0 :(得分:7)

以下行只是从第0个索引

开始将所有元素插入到arraylist中
p.addAll(0,lhm);

并且,使用这些行添加的元素仍然存在于arraylist中:

p.add(new Price("Banana", 60));
p.add(new Price("Apple", 80));

因此,在添加来自linkedhashset的项目之前,您应该清除数组列表,以防您不想要重复项。即。

p.clear();
p.addAll(lhm); // and, at this point you don't need the index.

答案 1 :(得分:4)

See this full solution may be help you


import java.util.ArrayList;
import java.util.LinkedHashSet;
import java.util.List;
import java.util.Set;
public class LinkedHashSetToList {

        public static void main(String[] args) {
        Set<String> lhs = new LinkedHashSet<String>();
        lhs.add("mumbai");
        lhs.add("delhi");
        lhs.add("kolkata");
        lhs.add("chandigarh");
        lhs.add("dehradun");
        //print linkedhashset
        System.out.println(" lhs is = "+lhs);
        List<String> list = new ArrayList<String>(lhs);
        // print arraylist
        System.out.println(" ArrayList Is = "+list);

    }

}



Output:
lhs is = [mumbai, delhi, kolkata, chandigarh, dehradun]
ArrayList Is = [mumbai, delhi, kolkata, chandigarh, dehradun]

 Reference : [How to Convert a LinkedHashSet to ArrayList][1]


  [1]: http://www.javaproficiency.com/2015/06/how-to-convert-linkedhashset-to.html

答案 2 :(得分:2)

Set只会确保其拥有的元素是唯一的。除非通过集合过滤整个集合,否则您不能指望ArrayList排除重复项。例如:

...
p.addAll(0,lhm);
p = new ArrayList<String>(new HashSet<String>(p));