我有一个自定义ArrayAdapter<Summary>
,其中包含一系列事件。 List<Summary>
中有重复的值,因此我尝试将List<Summary>
的值设置为LinkedHashSet<Summary>
,但这会显示一个空白页。
如何将自定义ArrayList
转换为LinkedHashSet
以获取唯一数据?
Main.java:
LinkedHashSet<Summary> listToSet = new LinkedHashSet<Summary>();
final List<Summary> summaries = new ArrayList<Summary>();
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.events_summary, container, false);
.......
setListView(month, year, date_value);
summaryAdapter = new SummaryAdapter(this.getActivity().getApplicationContext(), R.layout.listview_item_row, listToSet);
calendarSummary = (ListView) v.findViewById(R.id.calendarSummary);
calendarSummary.setAdapter(summaryAdapter);
return v;
}
public void setListView(int month, int year, int dv) {
events = new HolidayEvents();
_calendar = Calendar.getInstance(Locale.getDefault());
int totalDays = _calendar.getActualMaximum(Calendar.DAY_OF_MONTH);
for(int i = 1; i <= totalDays; i++){
if(isHoliday(i, month, year, dv))
{
date = i + " " + getMonthForInt(month-1) + " " + year;
for (Event event : events.eventDetails(this, month, i))
{
summaries.add(new Summary(date, event.eventdetails));
listToSet.addAll(summaries);
}
}
}
}
ArrayAdapter.java:
public class SummaryAdapter extends ArrayAdapter<Summary>{
Context context;
int layoutResourceId;
LayoutInflater mInflater;
LinkedHashSet<Summary> list = null;
List<Summary> data = null;
public SummaryAdapter(Context context, int layoutResourceId, LinkedHashSet<Summary> summaries) {
super(context, layoutResourceId);
this.layoutResourceId = layoutResourceId;
this.context = context;
this.list = summaries;
data = new ArrayList<Summary>(list); //converting LinkedHashSet to List
mInflater = LayoutInflater.from(context);
}
....rest of the code retrieving data by using data.get(position) ...
答案 0 :(得分:0)
您需要确保正确放入Set的类会覆盖Equals和hashCode函数。
让我们看看hashCode没有被覆盖的情况:
import java.util.*;
public class Example {
public static class Abc {
protected String s;
public Abc(String s) {
this.s = s;
}
@Override
public boolean equals(Object other) {
if (other instanceof Abc) {
return ((Abc) other).s.equals(this.s);
}
return false;
}
@Override
public int hashCode() {
return (int) (Math.random() * Integer.MAX_VALUE);
}
public String toString() {
return "Abc: " + this.s;
}
}
public static void main(String[] args) {
ArrayList<Abc> ar = new ArrayList<>();
ar.add(new Abc("a"));
ar.add(new Abc("a"));
ar.add(new Abc("a"));
LinkedHashSet<Abc> lhs = new LinkedHashSet<>(ar);
System.out.println("ar: " + ar);
System.out.println("LinkedHashSet: " + lhs);
}
}
这将产生:
ar:[Abc:a,Abc:a,Abc:a] LinkedHashSet:[Abc:a,Abc:a,Abc:a]
即使equals正确实施。 我相信您可能需要仔细检查HashCodes和Equals的正确实现。