Hulloes SO!
好的,我的情况是这样的:我有一个数据库,我需要从4个不同的表中进行SELECT,得到结果,其中一个表中的foregin键与我其他3个表中的id匹配。
结构:
CREATE TABLE IF NOT EXISTS `languages` (
`id` int(11) NOT NULL,
`lang_name` varchar(64) COLLATE utf8_bin NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;
CREATE TABLE IF NOT EXISTS `main_keys` (
`id` int(11) NOT NULL,
`project` int(11) NOT NULL,
`key` text COLLATE utf8_bin NOT NULL,
`comment` varchar(128) COLLATE utf8_bin NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;
CREATE TABLE IF NOT EXISTS `projects` (
`id` int(11) NOT NULL,
`project_name` varchar(64) COLLATE utf8_bin NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;
CREATE TABLE IF NOT EXISTS `translations` (
`id` int(11) NOT NULL,
`project` int(11) NOT NULL,
`key` int(11) NOT NULL,
`language` int(11) NOT NULL,
`translation` text COLLATE utf8_bin NOT NULL,
`lastedit` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;
translations
表是包含所有关系的表格(translations.project
=> project.id
,translations.key
=> main_keys.id
和{{1 }} => translations.language
)。
Relational overview http://assets.brianemilius.com/locale_relations.png
我当前的查询看起来像这样
language.id
我从特定项目(p.id)和特定语言(l.id)中选择,我想要一个结果,显示如下:
SELECT t.id, mk.key, t.translation, mk.comment, p.project_name, t.lastedit
FROM translations t
INNER JOIN languages l ON l.id = t.language
INNER JOIN main_keys mk ON mk.id = t.key
INNER JOIN projects p ON p.id = mk.project
WHERE p.id = '1' AND l.id = '2'
第2行和第3行表示没有翻译的结果。
但我只得到1行结果 - 顶部的结果为id 2(因为目前表+----+--------------+-------------+---------------------------+-----------------------+---------------------+
| id | key | translation | comment | project_name | lastedit |
+----+--------------+-------------+---------------------------+-----------------------+---------------------+
| 2 | Hello World! | Hej verden! | Test key for dev purposes | Locale Administrator | 2015-02-24 12:37:28 |
+----+--------------+-------------+---------------------------+-----------------------+---------------------+
| | test key | | Test key for dev purposes | Locale Administrator | |
+----+--------------+-------------+---------------------------+-----------------------+---------------------+
| | test key 2 | | Test key for dev purposes | Locale Administrator | |
+----+--------------+-------------+---------------------------+-----------------------+---------------------+
中只有一个翻译行)。
我在我的查询中尝试了LEFT和RIGHT JOIN的各种组合,但似乎没有任何帮助。我是在轨道还是我需要完全重新思考?
答案 0 :(得分:2)
我认为您需要重新考虑一下并使用main_keys
表作为主要来源,然后加入其他表:
SELECT t.id, mk.key, t.translation, mk.comment, p.project_name, t.lastedit
FROM main_keys mk
LEFT JOIN translations t ON mk.id = t.key
LEFT JOIN languages l ON l.id = t.language
LEFT JOIN projects p ON p.id = mk.project
WHERE p.id = 1 AND l.id = 2 OR l.id IS null;