Bash Script奇怪

Question

这段代码会给出什么，这不是真正的错误，但它让我发疯了......

#!/bin/bash 
# This script opens 4 terminal windows.
i="0"

while [ $i -lt 4 ]
do
xterm &
i=$[$i+1]


done
exit 0

这是我运行时得到的......

Ghost abrandt $ ./My4Terminals 
Ghost abrandt $ Warning: Tried to connect to session manager, None of the authentication protocols specified are supported
Warning: Tried to connect to session manager, None of the authentication protocols specified are supported
Warning: Warning: Tried to connect to session manager, None of the authentication protocols specified are supported
Tried to connect to session manager, None of the authentication protocols specified are supported

Ghost abrandt $

Answer 1

我想通了，我只需要取消设置会话管理器的选项：

 $ unset SESSION_MANAGER 

现在就像魅力......