Question

我有以下代码：

SELECT distinct userinfo.userid,userinfo.name,timeframe,deptname from EarlyOut
INNER JOIN userinfo ON USERINFO.USERID = earlyout.USERID
INNDER JOIN DEPARTMENTS ON DEPARTMENTS.DEPTID = EarlyOut.DEFAULTDEPTID
 where date>='2015-02-01' and date<='2015-02-28' and
DEPARTMENTS.DEPTNAME = 'abc'

现在从上面的代码我得到以下答案：

userid  name    timeframe             deptname
111     xyz     2015-02-05 08:00:00    abc 
111     xyz     2015-02-10 09:15:00    abc

现在我想要following输出：

userid  name    timeframe             deptname
111     xyz     17:15:00                abc

我想要总时间

那我怎么能这样做？

Answer 1

试试这个：

SELECT DISTINCT userinfo.userid,
                userinfo.name,
                Dateadd(ms, Sum(Datediff(ms, '00:00:00.000', timeframe)), '00:00:00.000') AS newtimeframe,
                deptname
FROM   EarlyOut
       INNER JOIN userinfo
               ON USERINFO.USERID = earlyout.USERID
       INNER JOIN DEPARTMENTS
               ON DEPARTMENTS.DEPTID = EarlyOut.DEFAULTDEPTID
WHERE  date >= '2015-02-01'
       AND date <= '2015-02-28'
       AND DEPARTMENTS.DEPTNAME = 'abc'
GROUP  BY userinfo.userid,
          userinfo.name,
          DEPARTMENTS.DEPTNAME

怎么做两个不同时间的总和

1 个答案: