Question

我正在尝试使用php解码来自我的Android应用程序的json。但是它返回一个空字符串

这是我的代码

$json="{account0Name: 'shamonsha665@gmail.com',account0Type: 'com.google',account1Name: 'mail.root5s@gmail.com',account1Type: 'com.google',account2Name: 'shamonwaste@gmail.com',account2Type: 'com.google',account3Name: '911.gksfapp@gmail.com',account3Type: 'com.google',account4Name: 'developer.root5@gmail.com',account4Type: 'com.google',account5Name: 'personal.root5@gmail.com',account5Type: 'com.google',account6Name: 'WhatsApp',account6Type: 'com.whatsapp',account7Name: 'shamonsha665@gmail.com',account7Type: 'com.linkedin.android',account8Name: '7736527089',account8Type: 'com.facebook.auth.login',deviceID: '911380450169267',phoneNo: '779808980',netCountry: 'in',netName: 'XXX',simNo: '8991197239007526600',simCountry: 'iX',simName: '!XX'}";

$owners=json_decode($json,true);
var_dump($owners);

var_dump()返回空值

这是我的json来源

var deviceInfo = cordova.require("cordova/plugin/DeviceInformation");
    deviceInfo.get(function(result) {
    //get the plugin result 
     owner=JSON.stringify(result);
    $.ajax({
        type: 'POST',
        url: 'http://ww.xxx.com/app/testjson.php',
        data:{'owner':owner},
        success: function(msg) {
          alert("from server"+msg);
        },
        error:function(err){
            alert("error"+JSON.stringify(err));
        }
      });
},, function() {
            console.log("error");
        });

Answer 1

也许这有帮助。

<?php
$json="{account0Name: 'shamonsha665@gmail.com',account0Type: 'com.google',account1Name: 'mail.root5s@gmail.com',account1Type: 'com.google',account2Name: 'shamonwaste@gmail.com',account2Type: 'com.google',account3Name: '911.gksfapp@gmail.com',account3Type: 'com.google',account4Name: 'developer.root5@gmail.com',account4Type: 'com.google',account5Name: 'personal.root5@gmail.com',account5Type: 'com.google',account6Name: 'WhatsApp',account6Type: 'com.whatsapp',account7Name: 'shamonsha665@gmail.com',account7Type: 'com.linkedin.android',account8Name: '7736527089',account8Type: 'com.facebook.auth.login',deviceID: '911380450169267',phoneNo: '779808980',netCountry: 'in',netName: 'XXX',simNo: '8991197239007526600',simCountry: 'iX',simName: '!XX'}";

$json = str_replace(array("'", ': "', ',', '{'), array('"', '": "', ',"', '{"'), $json);

$owners = json_decode($json);
print_r($owners);

?>

注意：对于另一个json，str_replace可能无法正常工作。

更新：获取价值

print_r($owners);
echo $owners->account0Name; // access object directly

$ownersArray = get_object_vars($owners); // convert to array
print_r($ownersArray);
echo $ownersArray['account0Name']; // and access by index

Answer 2

@Root它因为你正在解码一个你没有编码的json字符串，所以它什么都不解码。试试这个：

`$json="{account0Name: 'shamonsha665@gmail.com',account0Type: 'com.google',account1Name: 'mail.root5s@gmail.com',account1Type: 'com.google',account2Name: 'shamonwaste@gmail.com',account2Type: 'com.google',account3Name: '911.gksfapp@gmail.com',account3Type: 'com.google',account4Name: 'developer.root5@gmail.com',account4Type: 'com.google',account5Name: 'personal.root5@gmail.com',account5Type: 'com.google',account6Name: 'WhatsApp',account6Type: 'com.whatsapp',account7Name: 'shamonsha665@gmail.com',account7Type: 'com.linkedin.android',account8Name: '7736527089',account8Type: 'com.facebook.auth.login',deviceID: '911380450169267',phoneNo: '779808980',netCountry: 'in',netName: 'XXX',simNo: '8991197239007526600',simCountry: 'iX',simName: '!XX'}";
$json = json_encode($json);

var_dump(json_decode($json));`

这完全有效。 string(738) "{account0Name: 'shamonsha665@gmail.com',account0Type: 'com.google',account1Name: 'mail.root5s@gmail.com',account1Type: 'com.google',account2Name: 'shamonwaste@gmail.com',account2Type: 'com.google',account3Name: '911.gksfapp@gmail.com',account3Type: 'com.google',account4Name: 'developer.root5@gmail.com',account4Type: 'com.google',account5Name: 'personal.root5@gmail.com',account5Type: 'com.google',account6Name: 'WhatsApp',account6Type: 'com.whatsapp',account7Name: 'shamonsha665@gmail.com',account7Type: 'com.linkedin.android',account8Name: '7736527089',account8Type: 'com.facebook.auth.login',deviceID: '911380450169267',phoneNo: '779808980',netCountry: 'in',netName: 'XXX',simNo: '8991197239007526600',simCountry: 'iX',simName: '!XX'}"

Answer 3

您的JSON无效。

应该是这样的：

{"account0Name": "shamonsha665@gmail.com",...

等等。

Answer 4

您的Json字符串错误。您可以更改您的json字符串，如下所示。

试试这段代码： -

   <?php
        $json='{"account0Name": "shamonsha665@gmail.com","account0Type": "com.google","account1Name": "mail.root5s@gmail.com",.........}';
        $obj = json_decode($json, true);
       print_r($obj);
    ?>

我认为这对您的要求很有用。

PHP中的JSON解码失败

4 个答案: