Question

我想把这个json String传递给我的查询

xxxxxx=createVenue&clientId=2&jsonString={"veneue":{"clientId":"b","name":"d","tagline":"f","phone":"b","address":"d","city":"f","state":"b","zip":"d","twitter":"f","license":"d","imagePath":"f","pickupLocation":"b"},"drinks":[{"type":"d","name":"f","servingTable":{"servingSize":"b","price":"d"}},{"type":"d","name":"f","servingTable":{"servingSize":"b","price":"d"}}],"spirits":[{"type":"d","name":"f","servingTable":{"servingSize":"b","price":"d"}},{"type":"d","name":"f","servingTable":{"servingSize":"b","price":"d"}}]}

但是当我在php中对它进行解码时，它会返回null。

$clientId = trim($_REQUEST['clientId']);
        $jsonString = trim($_REQUEST['jsonString']);
        $decodedJSON = json_decode($jsonString);

        return $decodedJSON;

$ decoding JSON返回null;

有什么问题？

Answer 1

你的json似乎有效。
由于你启用了magic_quotes_gpc，引号可能会被反斜杠转义。你需要做的是使用

$jsonString = trim(stripslashes ($_REQUEST['jsonString']));

Answer 2

在解析之前尝试输出像die(trim($_REQUEST['jsonString']));这样的值 - 你会看到字符串已损坏

因此将此字符串插入到网址中的问题，在那个地方您应该urlencode(json_encode(...))

解码返回null的JSON字符串解码

2 个答案: