我使用MYS和使用JOIN的经验非常有限,现在遇到了障碍。
我有一个包含产品列表的主表。每种产品都有多种属性,如颜色,大小,品牌(每个产品的列/字段)。而不是为每个存储文本我使用number_id。
1. Yellow
2. Blue
3. Sony
4. Microsoft
5. Green
所以我想要一个记录
Name, Colour, Brand
Controller, 1, 3 = Controler, Yellow, Sony.
SELECT
product_data.id AS id,
product_data.title AS title,
product_data.compatability AS compatability,
product_data.release_date AS release_date,
product_data.colour AS colour,
product_data.brand AS brand,
product_data.type_accessory AS type_accessory,
product_data.created_userinfo AS created_userinfo,
product_data.created_timestamp AS created_timestamp
FROM product_data
INNER JOIN product_attributes
</code>
但是我现在还不确定如何更改“AS”颜色&#39;等于文字&#39; YELLOW&#39;而不是&#39; 1&#39;
<code>
[id] => 13413
[title] => Controler
[compatability] =>
[release_date] => 2016
[colour] => 1
[brand] => 3
[type_accessory] => 54
[created_userinfo] => TEST-USER
[created_timestamp] => 1425476393
[category_main_id] => 4
[category_main_description] => Video Game Accessories
[category_sub_id] => 43
[category_sub_description] => Microsoft Xbox One
[colour1] => 1
</code>
我做了以下更改,但我在颜色中得到空值。
SELECT
product_data.title AS title,
colours.name AS colour
FROM product_data
INNER JOIN colours ON colours.id_colour = product_data.colour
WHERE
product_data.created_userinfo = 'TEST-USER'
ORDER BY
title
</code>
<code>
Array
(
[0] => Array
(
[title] => Controller
[colour] =>
[category_main] =>
[category_sub] =>
[brand] =>
)
[1] => Array
(
[title] => Controller Wifi
[colour] =>
[category_main] =>
[category_sub] =>
[brand] =>
)
)
</code>
答案 0 :(得分:1)
您应该将属性保存在每个不同的表中,例如:
CREATE TABLE colours(
id_colour int PRIMARY KEY,
name varchar(255)
);
在名为color的字段的主表product_data中,您应该保留颜色的id。然后你可以像这样查询:
SELECT
product_data.id AS id,
product_data.title AS title,
product_data.compatability AS compatability,
product_data.release_date AS release_date,
colours.name AS colour
FROM product_data
INNER JOIN colours ON colours.id_colour = product_data.colour
PS。如果列名中没有冲突,您可以在查询中保留表名。
SELECT
id AS id,
title AS title,
compatability AS compatability,
release_date AS release_date,
name AS colour
FROM product_data
INNER JOIN colours ON colours.id_colour = product_data.colour
编辑:
请记住,product_data.id_colour和colours.id_colour字段必须具有相同的数据类型 - &gt;中间体
答案 1 :(得分:0)
您必须定义一个名为颜色的表格,列 ID 和名称,然后您的查询将如下所示:
SELECT
product_data.id,
product_data.title,
colour.name AS colour
FROM product_data
INNER JOIN colour ON colour.id = product_data.colour